2: Determine the size of two parallel reinforced concrete pipe culverts (n=0.012) to carry a discharge of 50 cms with a head loss of 3.0m for outlet control. as shown in the sketch below, the culvert is 30m long with square edge entrance on a slope of 1.0 percent, and both exit and entrance submerged. HW207.4 m- H E 202.0 m H₁ = 3.0 m n = 0.012 2 parallel RCP TW 204.4 m O=50 CMS, S = 0.01 L-30 m

A box culvert of (3x3)ft designed to accommodate 135 ft3/sec. the culvert length and slope are 100 ft and 2.5%, respectively. The elevation of headwater (point1) is 30 ft. The tailwater depth is 5 ft. Determine whether it is under inlet or outlet control. Ke= 0.7 and manning coefficient is 0.012 H HW ho -3 Slope So SUBMERGED OUTLET CULVERT FLOWING FULL

Question 4. L a) A (3.0 + X) m wide rectangular channel carries water at 20°C at a depth of 0.75 m. The channel is laid on a slope of 0.0004. Find the hydrodynamic nature of the surface if the channel is made of (a) very smooth concrete and (b) rough concrete. Also estimate the discharge for both the cases using Manning's formula. Consider that the equivalent roughness height for very smooth concrete is 0.25 mm and for rough concrete is 3.5 mm. Where, X = 0.01 x Last Three Digit of your Student ID b) Compute the normal depth and velocity in a trapezoidal channel whose bottom width is (6 + X) m and side slope is 1.75: 1. The discharge of the channel should be maintained 33 m/s. Consider that the value of Manning's n is 0.025 and bed slope is 0.0031. Where, X 0.01 x Last Three Digit of your Student ID

2. What uniform stage of flow exist in a circular conduit 2.0 m in diameter when the depth of flow is 175 cm, if it is laid on a slope of 0.175 using Chezy and Kutter's C formula with n = 0.025? 3. A triangular channel has a vertex angle equal to 90°. If the discharge uniformly flowing in the canal is 1.50 m/s and coefficient of roughness n = 0.030, compute the critical slope using Manning's equation.

PLEASE ANSWER QUESTION #3

1. Determine the discharge rate through three parallel corrugated metal pipe culverts shown in the sketch below (Use the outlet control). The 48-inch diameter culverts have a Manning, n value of 0.024. The culverts are 80 ft long, laid on a slope of 0.04, and have a projecting inlet and outlet. The culvert inlet bottom elevation is 302 ft with a head water elevation of 308.2 ft and a tailwater elevation of 302 ft. Use Ke = 0.8, Ko = 1.0. What is the discharge through the culvert (Use inlet control) with C₁ = 0.62. HW= 308.2 ft H=6.2 ft 302.0 ft BIBIE 3 Parallel CMP D= 48 inch S=0.04 TW 302.0 ft n=0.024 L = 80 ft

A concrete circular culvert (n=0.012) with a diameter of 2m is laid @ a slope of 0.3%. During non-peak flow, the depth of water flowing on the culvert is 25% of the diameter of the culvert. Determine the velocity & flow rate if a. the culvert is flowing full b. non-peak flow

A concrete lined channel is to be constructed. For concrete in this case take Manning’s n to be 0.014s/m1/3 The slope of the ground surface is 1 in 450. The design discharge is 8.5m3/s. The channel is to be designed with the optimum hydraulic section, but the exact dimensions and profile of the channel are yet to be determined. Calculate the optimum hydraulic section for a trapezoidal channel and sketch the section with the key dims. Shape of section Area of flow Wetted perimeter Hydraulic Radius Surface Width Hydraulic mean depth Trapezoid: half of a hexagon 1.732D2 3.463D 0.500D 2.309D 0.750D

A concrete pipe culvert is to be constructed under road to carry a maximum discharge 9 m3 /sec. If the length of pipe culvert 10 m on slope 1/100, ?? = 0.5, ?? = 1, n = 0.018, ?? = 0.18. Find the diameter of the pipe.

A. Design a trapezoidal channel to carry a discharge of 10.5 m^3/s. The bottom slop of the channel is 0.0035. Also the flow depth is half of the channel bottom width. Take roughness coefficient as 0.025 and side slop as 1H to 4V. B. Based on the given information and your results in part A, compute the state of flow