(2) Choose the one alternative that best completes the statement or answers the question. Assume two independent random samples are available which provide sample proportions. For the first sample assume n₁ = 100 and x₁= 39. For the second sample, assum n₂= 100 and x₂= 49. Test the null hypothesis that the population proportions are equal versus the alternative hypothesis that the proportions are not equal at the 90% confidence level. Frame the test statistic by subtracting the proportion for population 1 from that for population 2. Picl an appropriate z value, p-value and conclusion. Round your answer to the nearest thousandth. Note that this is a two- tailed test. z-value = -1.425 p-value= 0.077 statistically significant z-value = 1.425 p-value= 0.077 statistically significant z-value = -1.425 p-value= 0.077 not statistically significant z-value = 1.425 p-value= 0.154 statistically not significant

Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds.  Find the t and calculate a 95% (α = .05) confidence interval.

A random sample of 328 medical doctors showed that 171 had a solo practice. Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate ?̂ for p, also find a 95% confidence interval for p.

Statistics Question

Suppose a test is given to 20 randomly selected college freshmen in Ohio. The sample average score on the test is 12 points and the sample standard deviation is 4 points. Suppose the same test is given to 16 randomly selected college freshmen in Iowa. The sample average score on the test is 8 points and the sample standard deviation is 3 points. We want to test whether there is a significant difference in scores of college freshmen in Ohio versus Iowa. Does the 90% confidence interval indicate that there is evidence of a difference in population means? Group of answer choices Yes Not enough information No

A football coach claims that the average weight of all opposing teams’ members is 225 pounds. For a test of the claim, a simple random sample of 50 players is taken from all the opposing teams. The mean is found to be 230 pounds with a standard of 15 pounds. Construct a 95% confidence interval for the unknown average weight of the population of all the players of opposing teams. Interpret your result.

A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?

Use the Student's t distribution to find tc for a 0.99 confidence level when the sample is 11. USE SALT

A telephone poll of 500 adult Americans was reported in an issue of Time Magazine.  One of the questions asked was “What is the main problem facing the country?”   Thirty percent answered “crime”.  We are interested in the population proportion of adult Americans who feel that crime is the main problem. Define the random variables X and P’ in words. Which distribution should be used for this problem? Explain your choice. Construct a 97% confidence interval for the population proportion of adult Americans who feel that crime is the main problem.      i.   State the confidence interval,   ii.  Sketch the graph,  iii. Calculate the error bound 4.  Suppose we want to lower the sampling error. What is one way to accomplish that?