What sample size should the flower shop take?

In a survey of 500 students, 327 said they were planning to stay in town for the holidays.  What is the point estimate for the proportion of students staying home for the holidays? Construct the 95% confidence interval for the proportion of students staying home for the holidays.  Assume all requirements have been met.

A newspaper article reported that 400 people in one state were surveyed and 70% were opposed to a recent court decision. The same article reported that a similar survey of 500 people in another state indicated opposition by only 40%. Construct a 95% confidence interval of the difference in population proportions based on the data.

If n=470 and p̂ (p-hat) = 0.65, construct a 95% confidence interval.

Suppose you calculate a 99% confidence interval of 14.71 to 21.64. Determine the margin of error.

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 27 students, she finds 3 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. i Agresti and Coull's method for constructing confidence intervals (Round to three decimal places as needed.) O A. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between and O B. The proportion of students who eat cauliflower on Jane's campus is between To deal with issues such as the distribution of p not following a normal distribution, A. Agresti and B. Coull proposed a modified approach to constructing confidence intervals for a proportion. A (1 - a) • 100%…

In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality. The 90% confidence interval estimate of all U.S residents satisfied with their water quality is

To estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.

I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)