53.164.468.6489523atio of 3 (i.e 581613659ge turbineir is 10 barreases its twhich increassure ratio18.721.424.430.237.944.5= 0.287 kJ/k683711744773808er system as follre of the air is 4K.> first turbine hae back up to 90pic efficiency of!) in kW:12>erfectly isentropic (i.e. T') in K: Compressed air with a flowrate of 6 kg/min flows through a two-stage turbine and heat exchanger system as follows:• At the entrance to the system (point 1), the pressure of the air is 10 bar and the temperature of the air is 459 K.• From 1-2 the air passes through a heat exchanger which increases its temperature to 902 K.• From 2-3 the air passes through a turbine, with a pressure ratio of 3 (i.e. P₂/P₂²p=3). This first turbine has an isentropic efficiency of 65%.• From 3-4 the air passes through a second heat exchanger, which increases its temperature back up to 902 K.• From 4-5 the air passes through a second turbine with a pressure ratio of 3 and an isentropic efficiency of 90%.The properties of air are: cp = 1.005 kJ/kgK, cv = 0.718 kJ/kgK, R = 0.287 kJ/kgK, and y = 1.4.Select the correct value for each of the following values:a. The heat transfer to the air in the first heat exchanger (i.e. Q) in kW:12b. The temperature of the air leaving the first turbine if it were perfectly isentropic (i.e. T¹_ ) in K:3c. The actual temperature of the air leaving the first turbine (i.e. T)in K:d. The actual temperature of the air leaving the second turbine (i.e. T_¸) in K:e. The magnitude of the net rate of work transfer from the system in kW:f. The change in specific entropy of the air between the start and end of the system in J/kgK:<

“Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Answered: 18.7 21.4 24.4 30.2 37.9 44.5

Engineering

Mechanical Engineering

18.7 21.4 24.4 30.2 37.9 44.5

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.

Question

53.1
64.4
68.6
489
523
atio of 3 (i.e 581
613
659
ge turbine
ir is 10 bar
reases its t
which increa
ssure ratio
18.7
21.4
24.4
30.2
37.9
44.5
= 0.287 kJ/k
683
711
744
773
808
er system as foll
re of the air is 4
K.
> first turbine ha
e back up to 90
pic efficiency of
!) in kW:
12
>erfectly isentropic (i.e. T') in K:

Compressed air with a flowrate of 6 kg/min flows through a two-stage turbine and heat exchanger system as follows:
• At the entrance to the system (point 1), the pressure of the air is 10 bar and the temperature of the air is 459 K.
• From 1-2 the air passes through a heat exchanger which increases its temperature to 902 K.
• From 2-3 the air passes through a turbine, with a pressure ratio of 3 (i.e. P₂/P₂²
p=3). This first turbine has an isentropic efficiency of 65%.
• From 3-4 the air passes through a second heat exchanger, which increases its temperature back up to 902 K.
• From 4-5 the air passes through a second turbine with a pressure ratio of 3 and an isentropic efficiency of 90%.
The properties of air are: cp = 1.005 kJ/kgK, cv = 0.718 kJ/kgK, R = 0.287 kJ/kgK, and y = 1.4.
Select the correct value for each of the following values:
a. The heat transfer to the air in the first heat exchanger (i.e. Q) in kW:
12
b. The temperature of the air leaving the first turbine if it were perfectly isentropic (i.e. T¹_ ) in K:
3
c. The actual temperature of the air leaving the first turbine (i.e. T)in K:
d. The actual temperature of the air leaving the second turbine (i.e. T_¸) in K:
e. The magnitude of the net rate of work transfer from the system in kW:
f. The change in specific entropy of the air between the start and end of the system in J/kgK:
<

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