16. The overall reaction for the glycolysis reaction is C6H₁2O6(aq) + 2NAD+ (aq) + 2ADP³- (aq) + 2HPO(aq) + 2H₂O(1) = 2CH3COCO₂ (aq) + 2NADH(aq) + 2ATP (aq) + 2H3O+ (aq). What is A,G at chemical equilibrium?
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- One sample of the globular protein peroxidase is hydrolyzed by heating with 6 M HC1. A second sample is denatured by treatment with acetone. a) How does the peroxidase structure change during hydrolysis? Will this change the biological activity of peroxidase? b) How does the peroxidase structure change during denatur-ation? Will this change the biological activity of perox-idase? c) Are either of these processes likely to be reversible?2B. S. aureus hemolysin B attacks the RBC cell membrane by hydrolyzing the sphingomyelin headgroup: ОН HN .R hemolysin B cuts this bond i) Draw a plausible mechanism of hydrolysis for this lipid headgroup. Let B- and BH be general base and general acid. 00-P-O LOR2 OR, ii) Why is this damaging to the overall membrane architecture of the RBC?at what substrate concentration is v= 5.0 mM s^-1 for the enzyme catalyzed hydrolysis of trehalose?
- Under standard conditions, is the oxidation of free FADH2 by ubiquinone sufficiently exergonic to drive the synthesis of ATP? (F = 96.5 kJ/V • mol) ubiquinone + 2H++ 2e¯ → ubiquinol E' = 0.045 V FAD + 2H++ 2e → FADH2 = E' -0.219 V ○ no, as oxidation of FADH2 by ubiquinone generates 33.6 kJ/mol ○ no, as oxidation of FADH2 by ubiquinone generates 50.9 kJ/mol ○ no, as oxidation of FADH2 by ubiquinone generates -25.5 kJ/mol ○ yes, as oxidation of FADH2 by ubiquinone generates -33.6 kJ/mol ○ yes, as oxidation of FADH2 by ubiquinone generates -50.9 kJ/mol2. Glvcolate is oxidized into Glvoxylate by cytochrome C using the glycolate oxidase enzyme. The two half- reactions are shown below in their standard reduction forms. но +2 H* (aq) + 2 e Glyoxylate Glycolate CytC-Fe* +e CytC-Fe a) What is the overall reaction in the enzyme redox reaction? b) Given that the (i) equilibrium constant at pH-7 and 25 C for the overall reaction in (a) is 2.14x10", and (i) the biochemical standard reduction potential of cytochrome C is +0.25 V, calculate the overall biochemical standard voltage at the enzyme (E") and the biochemical standard reduction potential of glyoxylate.the C) using fischer Projection, draw each for payoff phase of glycoly i Б.) G3Р ->1, 3-bPG 3) 3ры ->2ры 5X PEP - ручикate the reaction 2) 1, 3-bPG-) 3PG 4.) 2PG->рер
- there are A-D questions to this picture set up. A) What enzyme catalyzes this reaction? B) What is Delta G, please answer in Joules, K=19 C) If concentration of Glucose-1_Phosphate is 48.82 uM at equalibrium, what is the concentration of Glucose-6-phosphate in uM? D) If the reaction is NOT at equalibrium, what is delta G at 25C if the concentration of Glucose-1-phosphate is 15.04 uM and concentration of Glucose -6-phosphate is 1.62 mM? please answer in Joules and in significant figures. *note, 10^3uM in 1 mM Thank you!!. The optimal conditions for salivary lysozyme (hydrolyzing glycoproteins of bacterial wall) are 37 C - temperature and pH is 5.2. Explain the decrease in this enzyme activity if the temperature will rise up to 60 °C and pH will be changed to 8.0. To answer the question: a) draw the graph of the velocity dependency on temperature and pH; b) calculate the relative enzyme activity if 10 mg of lysozyme catalyzes the formation of 5 uM of the product per 2 minutes. Concidor NH3: 5.For an enzyme catalyzed reaction of the form: S + E → P + E, the rate of product formation, [P], is given by: d[P]/dt = k2[E}total [S] /(Km + [S]) = For the enzymatically catalyzed hydrolysis of ATP at 25 °C and pH 7.0, the Michaelis Menten constant, Km was found to be equal to 16.8 μmol L 1 and the value of k2[E]total was found to be 0.220 μmol L-¹s¹. Find the initial rate at an initial ATP concentration of 30.0 μmol L-1
- 10. In an abnormal hemoglobin variant known as Hemoglobin-Kariya, the lysine residues at position 40 in the ß-chains are replaced by glutamic acid residues. a) What effect would you expect this change to have on the quaternary structure and oxygen binding properties of hemoglobin? b) Draw a diagram to illustrate the difference in the oxygen binding curves that would be obtained with normal hemoglobin and Hemoglobin-Kariya.Glucose-6- phosphatase catalyzes the following reaction: glucose – 6-phosphate + H2O = glucose + phosphate. Glucose-6- phosphatase would be classified as a(n) a) kinase b) hydrolase c) lyase d) oxidoreductase If ∆G for a biochemical reaction has a positive value, this means: a) the reaction will proceed very rapidly b) the reaction will proceed very slowly c) the reaction will generate heat d) The reaction requires energy input to proceed. Which thermodynamic parameter do enzymes change? A) entropy b) activation energy c) enthalpy d) all of these Enzymes have which effect on the chemical equilibrium of a biochemical reaction? A) the equilibrium shifts to favor products b) the equilibrium shifts to favor reactants c) The equilibrium does not shift, but gets there faster d) a new equilibrium is formed8. Hypercholesterolemia is a frequent complication of diabetes mellitus in patients with prolonged hyperglycemia. Why a high level of glucose in blood causes hypercholesterolemia and atherosclerosis? For the answer explain: a) how glucose can interact with the proteins and the consequences of this reaction for the proteins; b) glycation of which proteins results in hypercholesterolemia; c) possible causes and complications of hypercholesterolemia.