Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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Question

Please solve question 16-109 below this in the follwoing way:

  • Please include a kinamatic diagram (one for velocity and one for acceleration).
  • Please DO NOT solve this using velocity analysis (cartesian vector analysis). I would like it to be solved using scalar method. We dont use 3D in this course. We only use scalar analysis for the relative velocity equation (writing the x and y components of the equation and solving the equations for the unknowns). I have attached a sample question with solution in order to get an idea on how to use the scalar method to solve my question. I would like question 16-109 to be solved in a similar way. Thank you for your understanding.

If you can solve it as soon as possible that would be great and I will give you a thumps up and positive feedback :)

2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity and angular acceleration of the connecting link CB at the instant shown. B Kimmetic Diagram (Velocity) First solve relative Velocity 8=45⁰ an, B 201 Link BC 60 A=3 radis "=30" VB VB = WAB· TAB = 3 (2) = 6 Ft/ √48 Vc #7 43° Vc = V8+ VCI3 Y-Direction 0 = -√₂ Sin 60° + V Sin 45° VC18: VB Sin 60° Sings" Link AB A Dic => WBC = TBC Ves7-35 3 с -7.35 Ft/ = 2.45 rad CCV Kinematic diogram (Acceleration) )30° School of Energy / Mechanical Engineering (0²12 = WAB TAB = 18 F²7/3² Ac=AB+ A430 n D A₁ = a + ² + ₁ + 0²/0²=² Foc=18 F√/5² B Y-Dination A₂ = ₂² +² + Link BC Link AB at=d-√√8=0 AB de t 45 "48 OFENB 048 A n 0-0 Sin 30- Sin 45+ Sinus 45° 46 0 = 18 Sin30-18 Sin 45° + De Sinus ⇒a=-5-27 ² X-Directions - Vc = V₂ Grobu - V</2 C0-45° WAB 2 AB=dge TBC BC section 16.5 Q 16-63 23 Vc = -6 Cos6⁰ + 7-35 C-45 Vc = 2.2 14/₂, Chers_ 5.27=1076 rad/2 XBC = TBC 3 Page 2 CCW
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Transcribed Image Text:2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity and angular acceleration of the connecting link CB at the instant shown. B Kimmetic Diagram (Velocity) First solve relative Velocity 8=45⁰ an, B 201 Link BC 60 A=3 radis "=30" VB VB = WAB· TAB = 3 (2) = 6 Ft/ √48 Vc #7 43° Vc = V8+ VCI3 Y-Direction 0 = -√₂ Sin 60° + V Sin 45° VC18: VB Sin 60° Sings" Link AB A Dic => WBC = TBC Ves7-35 3 с -7.35 Ft/ = 2.45 rad CCV Kinematic diogram (Acceleration) )30° School of Energy / Mechanical Engineering (0²12 = WAB TAB = 18 F²7/3² Ac=AB+ A430 n D A₁ = a + ² + ₁ + 0²/0²=² Foc=18 F√/5² B Y-Dination A₂ = ₂² +² + Link BC Link AB at=d-√√8=0 AB de t 45 "48 OFENB 048 A n 0-0 Sin 30- Sin 45+ Sinus 45° 46 0 = 18 Sin30-18 Sin 45° + De Sinus ⇒a=-5-27 ² X-Directions - Vc = V₂ Grobu - V</2 C0-45° WAB 2 AB=dge TBC BC section 16.5 Q 16-63 23 Vc = -6 Cos6⁰ + 7-35 C-45 Vc = 2.2 14/₂, Chers_ 5.27=1076 rad/2 XBC = TBC 3 Page 2 CCW
16-109. Member AB has the angular motions shown. Determine the angular velocity and angular acceleration of members CB and DC. 100 mm с D 60° 450 mm W = 2 rad/s AB %AB = 4 rad/s² Prob. 16-109 B 200 mm
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Transcribed Image Text:16-109. Member AB has the angular motions shown. Determine the angular velocity and angular acceleration of members CB and DC. 100 mm с D 60° 450 mm W = 2 rad/s AB %AB = 4 rad/s² Prob. 16-109 B 200 mm
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