Please solve question 16-109 below this in the follwoing way:Please include a kinamatic diagram (one for velocity and one for acceleration).Please DO NOT solve this using velocity analysis (cartesian vector analysis). I would like it to be solved using scalar method. We dont use 3D in this course. We only use scalar analysis for the relative velocity equation (writing the x and y components of the equation and solving the equations for the unknowns). I have attached a sample question with solution in order to get an idea on how to use the scalar method to solve my question. I would like question 16-109 to be solved in a similar way. Thank you for your understanding.If you can solve it as soon as possible that would be great and I will give you a thumps up and positive feedback :) 2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity andangular acceleration of the connecting link CB at the instant shown.BKimmetic Diagram(Velocity)First solve relativeVelocity8=45⁰an,B201Link BC60A=3 radis"=30"VBVB = WAB· TAB = 3 (2) = 6 Ft/√48Vc#743°Vc = V8+ VCI3Y-Direction0 = -√₂ Sin 60° + V Sin 45°VC18:VB Sin 60°Sings"Link ABADic=> WBC = TBCVes7-353с-7.35 Ft/= 2.45 radCCVKinematic diogram(Acceleration))30°School of Energy / Mechanical Engineering(0²12 = WAB TAB = 18 F²7/3²Ac=AB+ A430nDA₁ = a + ² + ₁ + 0²/0²=² Foc=18 F√/5²BY-DinationA₂ = ₂² +² +Link BCLink ABat=d-√√8=0ABdet45"48OFENB048An0-0 Sin 30- Sin 45+ Sinus45°460 = 18 Sin30-18 Sin 45° + De Sinus⇒a=-5-27 ²X-Directions- Vc = V₂ Grobu - V2 C0-45°WAB2AB=dge TBCBCsection 16.5Q 16-6323Vc = -6 Cos6⁰ + 7-35 C-45Vc = 2.2 14/₂,Chers_ 5.27=1076 rad/2XBC = TBC3Page 2CCW 16-109. Member AB has the angular motions shown.Determine the angular velocity and angular acceleration ofmembers CB and DC.100 mmсD60°450 mmW= 2 rad/sAB%AB = 4 rad/s²Prob. 16-109B200 mm

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Answered: 16-109. Member AB has the angular…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Please solve question 16-109 below this in the follwoing way:

Please include a kinamatic diagram (one for velocity and one for acceleration).
Please DO NOT solve this using velocity analysis (cartesian vector analysis). I would like it to be solved using scalar method. We dont use 3D in this course. We only use scalar analysis for the relative velocity equation (writing the x and y components of the equation and solving the equations for the unknowns). I have attached a sample question with solution in order to get an idea on how to use the scalar method to solve my question. I would like question 16-109 to be solved in a similar way. Thank you for your understanding.

If you can solve it as soon as possible that would be great and I will give you a thumps up and positive feedback :)

2. If the angular velocity of link AB is 3 rad/s. determine the velocity of the block at C and the angular velocity and
angular acceleration of the connecting link CB at the instant shown.
B
Kimmetic Diagram
(Velocity)
First solve relative
Velocity
8=45⁰
an,
B
201
Link BC
60
A=3 radis
"=30"
VB
VB = WAB· TAB = 3 (2) = 6 Ft/
√48
Vc
#7
43°
Vc = V8+ VCI3
Y-Direction
0 = -√₂ Sin 60° + V Sin 45°
VC18:
VB Sin 60°
Sings"
Link AB
A
Dic
=> WBC = TBC
Ves7-35
3
с
-7.35 Ft/
= 2.45 rad
CCV
Kinematic diogram
(Acceleration)
)30°
School of Energy / Mechanical Engineering
(0²12 = WAB TAB = 18 F²7/3²
Ac=AB+ A430
n
D
A₁ = a + ² + ₁ + 0²/0²=² Foc=18 F√/5²
B
Y-Dination
A₂ = ₂² +² +
Link BC
Link AB
at=d-√√8=0
AB
de
t
45
"48
OFENB
048
A
n
0-0 Sin 30- Sin 45+ Sinus
45°
46
0 = 18 Sin30-18 Sin 45° + De Sinus
⇒a=-5-27 ²
X-Directions
- Vc = V₂ Grobu - V</2 C0-45°
WAB
2
AB=dge TBC
BC
section 16.5
Q 16-63
23
Vc = -6 Cos6⁰ + 7-35 C-45
Vc = 2.2 14/₂,
Chers_ 5.27=1076 rad/2
XBC = TBC
3
Page 2
CCW

16-109. Member AB has the angular motions shown.
Determine the angular velocity and angular acceleration of
members CB and DC.
100 mm
с
D
60°
450 mm
W
= 2 rad/s
AB
%AB = 4 rad/s²
Prob. 16-109
B
200 mm

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