I was going over the equations for the notes in class and I had a thought. Based on the equations in the image, you could get negative propellant mass. So, I coded it in matlab and I got negative mass. How is that possible? I think I used practical values for the velocity and mass ratio and so on. Did I do something wrong?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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I was going over the equations for the notes in class and I had a thought. Based on the equations in the image, you could get negative propellant mass. So, I coded it in matlab and I got negative mass. How is that possible? I think I used practical values for the velocity and mass ratio and so on. Did I do something wrong?

dv_ideal
g0 = 9.81;
Isp
400;
m_pl
=
=
10000;
= 500;
finert = 0.25;
MR = exp(dv_ideal/(g0*Isp))
MR 12.7869
m_prop= (m_p1* (MR-1)*(1 - f_inert))/(1 - (f_inert*MR))
m_prop= -2.0121e+03
Transcribed Image Text:dv_ideal g0 = 9.81; Isp 400; m_pl = = 10000; = 500; finert = 0.25; MR = exp(dv_ideal/(g0*Isp)) MR 12.7869 m_prop= (m_p1* (MR-1)*(1 - f_inert))/(1 - (f_inert*MR)) m_prop= -2.0121e+03
AV ₂.
IDEAL
m PROP
=
4,000 m/s
=
- Jo Ise dr. (miz)
miz
MR₂
= 2.475
mfz
Main (MR₂ - 1) (1 - finert)
/-finert MR₂
4
Transcribed Image Text:AV ₂. IDEAL m PROP = 4,000 m/s = - Jo Ise dr. (miz) miz MR₂ = 2.475 mfz Main (MR₂ - 1) (1 - finert) /-finert MR₂ 4
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