- + 15 I - 2 I3 = 0 -8 (165 +14 5,] +15 (3.5 3 +25] - 2 =0 52.5 --8x165 + IS2S 38.05S 13 - 228-33 %3D f3 = -6 A

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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How did u get the negative 6 please explain 

 

-8 C, + 15 12-2 13 = 0
-8 (165 +14 ] +15 (3.5 + 25] -2 =0
52.5
ー-8yI65
+ ISA2S
38.055 13
- 228.33
%3D
f3 = -6 A
1.
Transcribed Image Text:-8 C, + 15 12-2 13 = 0 -8 (165 +14 ] +15 (3.5 + 25] -2 =0 52.5 ー-8yI65 + ISA2S 38.055 13 - 228.33 %3D f3 = -6 A 1.
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