For R1=8, R2=8, R3=13, R4=24, R5=29, V1=85 V, I1=2 A & I2=8, use the principle of superposition tofind io :I1R2WioR112wwR3ww+1R4V1R5io1 (in ampere) due to V1 only=Oa. 0.51341002307101Ob. -1.026820046142Oc. -1.540230069213Od. -0.51341002307101(Note that io=i01+io2+i03, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) io2 (in ampere) due to 12 only=Oa.0.9277621122789Ob. -4.6388105613945Oc. 2.3194052806973Od. -2.3194052806973(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)io3 (in ampere) due to 11 only=Oa.0.14201486798257Ob.1.4201486798257Oc. 0.71007433991284Od. -0.21302230197385(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)io (in ampere) =(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)Power dissipated by R2 (in watt) =

Given: A network, with, R1=8𝞨, R2=8𝞨,R3=13𝞨,R4=24𝞨, R5=29𝞨,V1==85 V, I1=2 A, I2=8 A, To…

Answered: For R1=8, R2=8, R3=13, R4=24, R5=29,…

For R1=8, R2=8, R3=13, R4=24, R5=29, V1=85 V, I1=2 A & I2=8, use the principle of superposition to find io : 11 ww R1 R2 D12 R3 +1 R4 V1 R5

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Nodal Analysis

In the analysis of any electric circuit, nodal analysis is the method of determining the potential difference or voltage between different nodes in an electric circuit. A node is a point where two or more branches connect each other. In the nodal analysis, the voltages are determined in the terms of branch currents. The nodal analysis is also known as the node voltage method or branch current method. The nodal analysis method is one of the several applications of Kirchhoff's Current Law (KCL).

Question

For R1=8, R2=8, R3=13, R4=24, R5=29, V1=85 V, I1=2 A & I2=8, use the principle of superposition to
find io :
I1
R2
W
io
R1
12
ww
R3
ww
+1
R4
V1
R5
io1 (in ampere) due to V1 only=
Oa. 0.51341002307101
Ob. -1.026820046142
Oc. -1.540230069213
Od. -0.51341002307101
(Note that io=i01+io2+i03, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)

io2 (in ampere) due to 12 only=
Oa.
0.9277621122789
Ob. -4.6388105613945
Oc. 2.3194052806973
Od. -2.3194052806973
(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)
io3 (in ampere) due to 11 only=
Oa.
0.14201486798257
Ob.
1.4201486798257
Oc. 0.71007433991284
Od. -0.21302230197385
(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)
io (in ampere) =
(Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1)
Power dissipated by R2 (in watt) =

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