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I+ Iェ-I,=0 R= 33052 生っ Lett: 6.98- luw I, -(00I; = 0 -(2) I. I, I3 Right : 15-330I2- lWT,=0 6.98V 15V (3) Vanls

I+ Iェ-I,=0 R= 33052 生っ Lett: 6.98- luw I, -(00I; = 0 -(2) I. I, I3 Right : 15-330I2- lWT,=0 6.98V 15V (3) Vanls

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Hello I need help solving this for the left and right side of this circuit. I have also provided a picture for reference.
wsbek C Conclusins Page is aya An a tup Procedure K Analy KCan 4 s DE Cent ery o et enr Chec a rced DC Setup DC Setue nesnter Check Theary cal Setp Signal Generater 13 Vo • Run #1 Run 1 Current Probe, Ch A (A) Mean DC Current Procedure: Volts Out, Ch 01 a50 Output 1 1. Cick open the Signal Generator at the left of the screen Set 850 Output 1 for a DC Waveform and a DC Voltage of 15 ck the Auto button 6.98V -3.63x10-4A Wefem DC 2. Cick Record (bottom left of screen 12 Vc 3. Wat several seconds until the measured current stops varying as the average becomes well defined. Cick Stop. 4. Enter the votage and current values in Table ill TOfet and Limi V Run 1 Vot. Ch C X Run 1 Q cal wege im 0.00V -.-mA CurrentLmt1A Auto Ths de T Aened an ina drent page etu he pege to TN M he ege tab step buten Tu may 4farent page Retu the e t Va cenfigure th tel en th paar for later use Volt. Ch B HRun #1 a cal 0.00V -.-mA 850 Output 2 50 Output 3 Table III: DC Circuit Voltages & Currants 13 (mA) VA 12 Vo (V) (mA) (mA) (V) 1 2 Note: Athough the total current, 13, is meas ured directly, 11 and 12 are cak ulated from the measured votage drops using AV/R-I. Although it would be nice to meas ure them directly, shfting the ammeter ground introduces error of a few mA which decreases the precision of the ex periment since the current values are qute small This realy is not a limitation on the res ults since this is what the ammeter does as wel. It measures the voltage drop across a 0.1 0 precision resistor. We have just made our own ammeters by replacing the 0.10 resistor with the known values for the resistors in the circut Contrul 00:04.38 wtage Senser. ChA se ce w: Raced Ca d edy Delet Lau Condine MMAM I,+I2-I,=0 - R= 33052 Let: 6-98- lw I, - l0 I; = 0 -(2) I, I Right : 15-330I2 - loT, =0 6.98 v I3 15V (3)
Transcribed Image Text:wsbek C Conclusins Page is aya An a tup Procedure K Analy KCan 4 s DE Cent ery o et enr Chec a rced DC Setup DC Setue nesnter Check Theary cal Setp Signal Generater 13 Vo • Run #1 Run 1 Current Probe, Ch A (A) Mean DC Current Procedure: Volts Out, Ch 01 a50 Output 1 1. Cick open the Signal Generator at the left of the screen Set 850 Output 1 for a DC Waveform and a DC Voltage of 15 ck the Auto button 6.98V -3.63x10-4A Wefem DC 2. Cick Record (bottom left of screen 12 Vc 3. Wat several seconds until the measured current stops varying as the average becomes well defined. Cick Stop. 4. Enter the votage and current values in Table ill TOfet and Limi V Run 1 Vot. Ch C X Run 1 Q cal wege im 0.00V -.-mA CurrentLmt1A Auto Ths de T Aened an ina drent page etu he pege to TN M he ege tab step buten Tu may 4farent page Retu the e t Va cenfigure th tel en th paar for later use Volt. Ch B HRun #1 a cal 0.00V -.-mA 850 Output 2 50 Output 3 Table III: DC Circuit Voltages & Currants 13 (mA) VA 12 Vo (V) (mA) (mA) (V) 1 2 Note: Athough the total current, 13, is meas ured directly, 11 and 12 are cak ulated from the measured votage drops using AV/R-I. Although it would be nice to meas ure them directly, shfting the ammeter ground introduces error of a few mA which decreases the precision of the ex periment since the current values are qute small This realy is not a limitation on the res ults since this is what the ammeter does as wel. It measures the voltage drop across a 0.1 0 precision resistor. We have just made our own ammeters by replacing the 0.10 resistor with the known values for the resistors in the circut Contrul 00:04.38 wtage Senser. ChA se ce w: Raced Ca d edy Delet Lau Condine MMAM I,+I2-I,=0 - R= 33052 Let: 6-98- lw I, - l0 I; = 0 -(2) I, I Right : 15-330I2 - loT, =0 6.98 v I3 15V (3)
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