13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m. The escape speed for an object launched from this planet's surface is 7.65 103 m/s. What is the acceleration due to gravity at the surface of the planet? Conservation of energy K1 +U1 = K2 + U2 Gravitational PE = - GMm/r; g = GM/r² When an object escapes from the gravitational field U = 0 at very far from the planet K =0 g = 9.03 m/s²

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Chapter6: Applications Of Newton's Laws
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Problem 76P: The CERN particle accelerator is circular with a circumference of 7.0 km. (a) What is the...
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(g = 9.03 m/s^2 is the answer but I need an explanations as to why it's the answer.)

13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m.
The escape speed for an object launched from this planet's surface
is 7.65 103 m/s. What is the acceleration due to gravity at the
surface of the planet?
Conservation of energy K1 +U1 = K2 + U2
Gravitational PE = - GMm/r; g = GM/r²
When an object escapes from the gravitational field U = 0 at very far from the planet K =0
g = 9.03 m/s²
Transcribed Image Text:13.19 .. A planet orbiting a distant star has radius 3.24 × 106 m. The escape speed for an object launched from this planet's surface is 7.65 103 m/s. What is the acceleration due to gravity at the surface of the planet? Conservation of energy K1 +U1 = K2 + U2 Gravitational PE = - GMm/r; g = GM/r² When an object escapes from the gravitational field U = 0 at very far from the planet K =0 g = 9.03 m/s²
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