11. Consider a network shown in the figure consisting of a resistance, a capacitor, an inductor and three alternating voltage sources 1, 2 and 3. Terminal voltages of the sources 1, 2 and 3 are v₁ = V₁ sin(cot), V₂ = V₁ sin(oot + 120°) and v3 = V₁ sin(ot+240) respectively and moduli of the reactance of the capacitor and the inductor are equal to the resistance. Then (A) Peak value of voltage at point P is vo (√3+1) (B) Peak value of voltage at point P is Vo (√3-1) (C) vp=vo (√3+ 1) sin(cot +90) Vo (D) vp = Vo (√3-1) sin(cot + 180)

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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11. Consider a network shown in the figure consisting of a resistance, a capacitor, an inductor and three alternating voltage sources 1, 2 and 3. Terminal voltages of the sources 1, 2 and 3 are v₁ = Vo sin(t), V₂ = Vo sin(cot +120°) and v3 = Vo sin(ot+240°) respectively and moduli of the reactance of the capacitor and the inductor are equal to the resistance. Then 10 3 P (A) Peak value of voltage at point P is vo (√3+1) (B) Peak value of voltage at point P is vo (√3-1) (C) Vp = Vo (√3+ 1) sin(oot +90) (D) vp = Vo (√3-1) sin(oot + 180)
11. Consider a network shown in the figure consisting of a resistance, a capacitor, an inductor and three
alternating voltage sources 1, 2 and 3. Terminal voltages of the sources 1, 2 and 3 are v₁ = V₁ sin(cot),
V₂ = V₁ sin(t+120°) and v3 = V₁ sin(cot+240) respectively and moduli of the reactance of the
capacitor and the inductor are equal to the resistance. Then
(A) Peak value of voltage at point P is vo (√3+1)
(B) Peak value of voltage at point P is vo (√3-1)
(C) vp = Vo (√3+1) sin(cot +90)
(D) vpvo (√3-1) sin(cot + 180)
Transcribed Image Text:11. Consider a network shown in the figure consisting of a resistance, a capacitor, an inductor and three alternating voltage sources 1, 2 and 3. Terminal voltages of the sources 1, 2 and 3 are v₁ = V₁ sin(cot), V₂ = V₁ sin(t+120°) and v3 = V₁ sin(cot+240) respectively and moduli of the reactance of the capacitor and the inductor are equal to the resistance. Then (A) Peak value of voltage at point P is vo (√3+1) (B) Peak value of voltage at point P is vo (√3-1) (C) vp = Vo (√3+1) sin(cot +90) (D) vpvo (√3-1) sin(cot + 180)
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