1.17 Figure P1.17 shows the stress-strain relations of metals A and B during tensiontests until fracture. Determine the following for the two metals (show all calcu-lations and units):a. Proportional limitb. Yield stress at an offset strain of 0.002 in./in.150 -- Metal A100• Metal B500.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14Strain, in./in.FIGURE P1.17c. Ultimate strengthd. Modulus of resiliencee. Toughnessf. Which metal is more ductile? Why?Stress, ksi

Any pressure of a solid object creates a stretched internal stress, similar to the spring-turning…

Answered: 1.17 Figure P1.17 shows the…

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter9: Time, Temperature, And Mechanical Properties

Section: Chapter Questions

Problem 9.3P

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The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen with a circular cross section. The diameter was 3 8 inch and the gage length (The length over which the elongation is measured) was 2 inches. a. Use the data in Table 1.5.2 to produce a table of stress and strain values. b. Plot the stress-strain data and draw a best-fit curve. c. Compute the, modulus of elasticity from the initial slope of the curve. d. Estimate the yield stress.
The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
Compare the engineering and true secant elastic moduli for the natural rubber in Example Problem 6.2 at an engineering strain of 6.0. Assume that the deformation is all elastic.
I5 In a tensile test experiment of carbon steel. a standard specimen (D= 0.505 in. Gauge length=2.0 in & total length 8 in) had a 0.2% offset yield strength of 80.000 psi and engineering strain of 0.010 at the yield strength point Calculate: The load (force) at this point. The instantaneous area of the specimen at this point. c. The true stress at this point. d. The true strain at this point. e. The total length of the specimen. if the load is released at this point.
A bar obtained by bonding together pieces of steel (Es = 29 x 106 psi) and brass (E = 15 x 106 psi) has the cross section shown (Fig. a). Determine the maximum stress in the steel and in the brass when the bar is in pure bending with a bending moment M = 40 kip-in. 0.4 in. 3 in. Brass 0.75 in. Steel Brass 0.4 in. (a) 1) Composite bar.
Strain = 600 Stress = Strain = 500 Stress = 400 500 300 400 300 200 200 100 100 0.000 0.002 0.004 0.006 Strain 0.00 0.04 0.08 0.12 0.16 0.20 Strain Stress (MPa)
The strain gauge measurement of a steel plate indicate the principle strains are 0.003 and 0.001. What is the value of major principle stress in MPa? (E = 200 GPa, μ = 0.33)
A steel rod with a cross sectional area of 120 (mm) ^2 is stretched between two fixed points. The tensile load at 20°C is 4200N. What will be the stress at-25°C? a=11.7x [10] ^(-6)/°C and E = 200GPA. See figure 06. * Figure 06 120 MPa 130 MPa 140 MPa 150 MPa
In the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Og = -90 MPa and the initial temperature %3D 20°C. 2) The final length of the aluminium member. Aluminum A=1800mm? Bronze A=1500mm? E=73GPA E=105GPA a=23.2x10-6/°C a=21.6x10-6/°C Gap=0.5mm 0.35m 0.45m
S Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion tests until fracture. Determine the following for the two metals (show all calculations and units): a. Proportional limit b. Yield stress at an offset strain of 0.002 m/m. c. Ultimate strength d. Modulus of resilience e. Toughness f. Which metal is more ductile? Why? 900 Metal A 600 Metal B 300 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 Strain, m/m FIGURE P1.16 Stress, MPa
2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. 18 in. Aluminum A = 2.8 in² Bronze A = 2.4 in² E = 15 × 10º psi a = 12 x 10-6/°F E = 10.6 × 106 psi α = 12.9 x 10-6/°F Fig. P2.58 and P2.59
A steel bar, whose cross section is 0.60 inch by 4.10 inches, was tested in tension. An axial load of P = 31,025 lb. produced a deformation of 0.115 inch over a gauge length of 2.10 inches and a decrease of 0.0080 inch in the 0.60-inch thickness of the bar. a. Determine the lateral strain. b. Determine the axial strain. c. Determine the Poisson’s ratio v. d. Determine the decrease in the 4.05-in. cross-sectional dimension (in inches).

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