1. The results of a standard Proctor test are given in Table Q1 below. Determine the maximum dry density of soil compaction and the optimum moisture content. Table Q1 Volume of Proctor Mass of wet soil in the mold Moisture content mold (cm³) (kg) (%) 987 3.39 11.5 987 3.87 13.5 987 4.22 15.5 987 5.11 17.5 987 4.75 19.5 987 4.31 21.5

1. The results of a standard Proctor test are given in Table Q1 below. Determine the maximum dry density of soil compaction and the optimum moisture content. Table Q1 Volume of Proctor Mass of wet soil in the mold Moisture content mold (cm³) (kg) (%) 987 3.39 11.5 987 3.87 13.5 987 4.22 15.5 987 5.11 17.5 987 4.75 19.5 987 4.31 21.5

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.7P

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Find the missed data and give the result of Fineness Modulus of sample soil data given below. Weight Percentage Cumulative Percentage finer Sieve retained Weight retained percentage N = (100 - C) S.NO size retained (C) Select one: (gm) (gm) O a. 7.824 1 75mm O b. 9.438 63mm O c. 8.142 3 50mm O d. 7.649 4 37.5mm 28mm 123 6.15 6.15 6 20mm 107 5.35 11.50 7 14mm 208 10.4 21.9 8 10mm 56 2.8 24.7 6.3mm 3.9 10 5.0mm 92 4.6 33.2 11 3.35mm 308 15.4 48.6 12 2.0mm 223 11.15 59.75 13 1.18mm 188 9.4 69.15 14 600µ 282 14.1 83.25 15 300µ 96 4.8 88.05 16 150µ 88 4.4 92.45 17 75µ 103 5.15 97.6 18 pan 48 2.4 100
5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight Content, % in Mold, gf Water 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point.
5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y, at Wopt? What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max?
2a. The following data was obtained from Liquid Limit Test conducted at a Soil Lab. Using the data given in Table 01, determine the following; Table 01: Liquid Limit Test data for the particular soil sample Liquid Limit Determination Specimen No. No. of Blows Wt. of Container Wt. of Container + Wet Soil Wt. of Container + Dry Soil i. ii. Unit 1 14 7.11 (g) (g) (g) 21.31 27.91 2 20 7.31 27.31 21.21 3 28 7.71 28.41 22.31 4 32 10.91 30.11 24.61 5 39 7.21 26.51 21.11 Determine the Liquid Limit and Flow Index If Plastic Limit of this soil is 22. Classify the soil based on BS Soil Classification system. I
(b) Classification tests for the determination of the particle size distribution of a soil produced the following results: Particle Size % finer (mm) 99 2.36 80 1.3 63 0.6 33 0.2 10 0.075 3 0.02 Then using cone penetrometer for Liquid Limit test, the results were recorded as follows. Cone penetration 15.9 17.7 19.1 20.3 22.5 (mm) Water 32.6 42.9 51.6 59.8 66.2 content (%) While the plastic limit test conducted for the same soil recorded as below:- Test No. 1 2 3 Wet soil 10.01 11.23 9.72 Dry soil 8.02 9.01 7.72 SKAA 1713 4 i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b). Calculate the uniformity coefficient, Cu and the coefficient of gradation, C, for the soil sample. Determine the plastic limit, the liquid limit and the plasticity index of the soil. Plot the graph to help you obtain the results (if necessary). ii) iii)
Question 8 (1) - Oedometer test What are the boundary conditions applied to a soil sample tested in an Oedometer? Z H a) Pore water pressure at z = H (top of the sample) is PH = Yw. H b) Ez = Ex c) &z=&v (₂ is the volumetric strain of the sample) d) At time t=0, 4p = 0
B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D10 = 70 μm L.L = 36% P.L = 31% D8 = 2 μm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%. J
The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya.max and wopt• (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y at w. (e) What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max? pt? opr?
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.
Problem Set 4 4. The following data were obtained from the liquid and plastic limit tests for a soil: Liquid Limit Test: Number of blows (N) Molsture content (%) a) Draw the flow curve from the liquid limit test data and find the liquid limit. (use excel to graph) b) What is the plasticity index of 17 42.1 22 38.2 27 36.2 32 34.1 Plastic Limit Test: Moisture content = 21.3% the soil?
Q': A- Classification tests have been performed on a soil sample and the grading curve that shown in (Fig. 1) and Atterberg limits obtained. Classify the soil using the USCS? L.L=32 and P.L=26 100 80 60 40 20 Fig. 1 0.1 1 Particle size (mm) 0.0001 0.001 0.01 10 100 % Finer
Find the value of Cc of the following soil data sample Weight Percentage Cumulative Percentage Sieve Weight retained (gm) percentage retained (C) retained finer S.NO Select one: O a. 10.85 size (gm) N = (100 - C) {W,/ W,} x 100 1 75mm 100 O b. 7.36 63mm 100 O c. 18.34 50mm 100 O d. 2,96 4 37.5mm 454 22.7 22.7 77.30 5 28mm 285 14.25 36.95 63.05 6 20mm 207 10.35 47.30 52.70 7 14mm 318 15.90 63.20 36.80 8 10mm 206 10.30 73.50 26.50 6.3mm 118 5.90 79.40 20.60 10 5.0mm 102 5.10 84.50 15.50 11 3.35mm 64 3.20 87.70 12.30 12 2.0mm 88 4.40 92.10 7.90 13 1.18mm 35 1.75 93.85 6.15 14 600µ 42 2.10 95.15 4.85 15 300µ 33 1.65 97.60 2.40 16 150µ 18 0.90 98.50 1.50 17 75µ 22 1.10 99.6 0.40 18 Pan 8 0.40 100 In the pan we have = 100 W,= 2000 2 -99.6 = 0.4 % of material 2. 3.