The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the table below. Water 6.2 8.1 9.8 11.5 12.3 13.2 Content (%) Unit Weight | (KN/m³) 16.9 18.7 19.5 20.5 20.4 20.1 ii) Determine the ranges of ya,field and OMC required for field compactions of 95% and 98%.

The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the table below. Water 6.2 8.1 9.8 11.5 12.3 13.2 Content (%) Unit Weight | (KN/m³) 16.9 18.7 19.5 20.5 20.4 20.1 ii) Determine the ranges of ya,field and OMC required for field compactions of 95% and 98%.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.15P

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The table below shows theresults of compaction test for a soil sample, Trial No. 1 3 4 w.c% 5.3 10.8 17 23 y dry, kN/m3 14.56 15.77 16.97 18.19 Gs 2.75 2.75 2.75 2.75 The trial No. is neglected Оз O 2 O 4 O 1
QUIZ 3 1. A sample of clay has a water content of 40 percent at full saturation. Its shnnkage limit is 15 percent. Assuming Gs = 2.70, determine its degree of shrinkage. Comment on the quality of the soil.
Laboratory compaction test results on a clayey silt are given in the following table:- Moisture content (%) Dry unit w3eight (kNm³) 14.80 8 17.45 18.52 11 18.9 12 18.6 14 16.9 Following are the results of a field unit weight determination test on the same soil with the sand cone method:- • Calibrated dry density of Ottawa sand = 1667 kg/m³ • Calibrated mass of Ottawa sand to fill the cone = 0.117 kg • Mass of jar + cone + sand (before use) = 5.99 kg • Mass of jar + cone + sand (after use) = 2.81 kg • Mass of moist soil from hole = 3.331 kg • Moisture content of moist soil = 11.6% Determine a. Dry unit weight of compaction in the field
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.
From the following data, solve for the degree of compaction. If this is for Item 201, Aggregate Base Course, will it pass the specification? Field density test data: Weight of material taken from hole, kg. = Weight of sand to fill hole, kg. = 5.585 3.935 Volume of hole, cu.m = Wet unit weight, kg/cu.m = Dry unit weight, kg/cu.m = 0.0028 1995 1734 Laboratory Data: Maximum dry density, kg/cu.m. = 1750 Optimum Moisture Content, % = 8.00
10. The results of a Standard Proctoretest is tabulated as follows: (SEE PICTURE) Determine the maximum dry unit weight of compaction Determine the optimum moisture content Determine the void ratio at the optimum moisture content Gs = 2.70 Determine the degree of saturation at the optimum moisture content A field unit determination test for the soil, yielded the following data. Moisture content = 12% and moist unit weight = 106 pcf. Determine the relative compaction.
The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the table below. Water 6.2 8.1 9.8 11.5 12.3 13.2 Content (%) Unit Weight | (KN/m³) 16.9 18.7 19.5 20.5 20.4 20.1 Determine: i) The optimum moisture content (OMC) and the maximum dry unit weight (MDW).
Soil Compaction Homework: the results of standard compaction test are shown in the table below. Determine the maximum dry unit weight and the optimum moisture content. W% 6.2 8.1 9.8 11.5 12.3 13.2 ybkN/m³ 18.7 20.4 16.9 19.5 20.5 20.1 а. What is the dry unit weight and w at 95% standard compaction? b. Determine the degree of saturation at the maximum yd , Gs = 2.7? С. Plot the zero air voids line?
Question 13 The compaction of a soil obtained from a standard compaction test is shown in the attached figure. At OMC (optimum moisture content) the degree of saturation = 93 %. What is the highest possible dry unit weight for this soil to have when the moisture content is 9 %? P (1+w) 20.0 1 10 Pa(s) 19.5 19.0 18.5 18.0 Dry unit weight, y, [kN/m³] 17.5 17.0 16.5 16.0 6 7 8 9 14. 1 10 11 12 13 14 Water content, w, [%] 15 16 G.P 1+ wG S 17 18
Table 1 below is the result of compaction results. Please evaluate the correct combination of missing data. Table 1: Compaction test results Water content (%) 8.00 III IV Bulk Density II 2.35 2.09 (Mg/m³) Dry Density (Mg/m³) 1.89 2.08 1.76 || A B Answer A B с D I 5.00 1.87 I 1.68Mg/m³ 1780kg/m³ 1.80Mg/m³ 1.78Mg/m³ 2.04Mg/m³ 2.08Mg/m³ 2080kg/m³ 2040kg/m³ III 13% 11% 12% 13% 16.00 2.20 1.90 IV 19% 20% 19% 19%
QUIZ 3 1. A sample of clay has a water content of 40 percent at full saturation. Its shninkage limit is 15 percent. Assuming Gs = 2.70, determine its degree of shrinkage. Comment on the quality of the soil.
1. Given Gs = 2.75, calculate the zero-air-void unit weight for a soil in lb/ft³ at w = 5%. 2. The result of a standard Proctor test are given below. Determine the maximum dry unit weight of compaction and the optimum moisture content. Volume of proctor mold Weight of wet soil in the mold Moisture content (%) (ft³) (lb) 1/30 3.26 8.4 1/30 4.15 10.2 1/30 4.67 12.3 1/30 4.02 14.6 1/30 3.63 16.8 3. Repeat No. 2 with the following details. Volume of proctor mold (cm³) Weight of wet soil in the mold (kg) Moisture content (%) 943.3 1.68 9.9 943.3 1.71 10.6 943.3 1.77 12.1 943.3 1.83 19.8 943.3 1.86 15.1