1. Steam distillation was performed to obtain geraniol (MM = 154.25 g/mol) from dried rose petals. At 99.25°C, the vapor pressure of water is 714 mmHg while that of geraniol was determined to be 46 mmHg. %3D a. Determine the theoretical mass of geraniol that will distill per 100 g of water. b. If 150 g of dried rose petals were used, calculate the percent yield of the distillation.

2. What mass of toluene (C6H5CH3) was added to 233.6 g of benzene (C6H6) if the vapor pressure of benzene became 61.8 mmHg.  The vapor pressure of pure benzene is 70.1 mmHg at 18 oC.  Answer to 1 decimal place.

At a certain temperature the vapor pressure of pure benzene (C6H6) is measured to be 0.68 atm. Suppose a solution is prepared by mixing 88.0 g of benzene and 64.1 g of thiophene (C4H4S). Calculate the partial pressure of benzene vapor above this solution. Round your answer to 2 significant digits. Note for advanced students: you may assume the solution is ideal. 0 atm 0x10 X

A solution is made by dissolving 0.0613 kg of biphenyl (C₁₂H₁₀) in 350.0 mL of benzene (C₆H₆). a.) If the boiling point of pure benzene is 80.1 °C, then what would be the boiling point of this solution in °C? (Kb for benzene is 2.53 °C/m and the density of benzene is 0.877 g/mL) b.) If the vapor pressure of pure benzene is 24.4 kPa at 40.0 °C, then what will the vapor pressure of the solution be in kPa? (Consider biphenyl to be nonvolatile and the density of benzene is 0.877 g/mL) c.) What would be the osmotic pressure (in atm) of this solution at 40.0 °C? (The density of benzene is 0.877 g/mL.)

Ethanol has a Kb of 1.22 ºC/m and usually boils at 78.4 ºC. What is the boiling point of a solution containing 85.0 g of sugar (MW = 342.34 g/mol) in 500.0 g ethanol?

At room temperature, toluene has a vapor pressure of 300mmHg and ethanol has a vapor pressure of 45mmHg. Let us assume that when equimolar amounts of these liquids are mixed together, heat is released. What can be said about the vapor pressure of the resulting solution? O The vapor pressure will be 172.5 mmHg because there are equal amounts of both liquids. O The vapor pressure is less than 172.5 mmHg because the reaction is exothermic. O The vapor pressure will be 300 mmHg because toluene has the greater vapor pressure, which cancels out the vapor pressure of ethanol. O The vapor pressure will be 345 mmHg because the vapor pressure values are additive.

A solution is prepared by dissolving 371 g of sucrose (C12H₂2O11) in 569 g of water. What is the vapor pressure of this solution at 30 °C? Be sure your answer has the correct number of significant digits. Note: Reference the Vapor pressure of water (H₂O) at selected temperatures table for additional information. Vapor pressure = mmHg x10 X 3

A solution is made by dissolving 0.0303 kg of biphenyl (C₁₂H₁₀) in 350.0 mL of benzene (C₆H₆).   - What intermolecular forces are shared between biphenyl and benzene?   - If the boiling point of pure benzene is 80.1 °C, then what would be the boiling point of this solution in °C? (Kb for benzene is 2.53 °C/m and the density of benzene is 0.877 g/mL)   - If the vapor pressure of pure benzene is 24.4 kPa at 40.0 °C, then what will the vapor pressure of the solution be in kPa? (Consider biphenyl to be nonvolatile and the density of benzene is 0.877 g/mL)   - What would be the osmotic pressure (in atm) of this solution at 40.0 °C? (The density of benzene is 0.877 g/mL.)

A solution is prepared by dissolving 23.8 g urea, (NH2)2Co, in 120.0 g water. Calculate the boiling point of the solution at a pressure of 1 atmosphere. Urea is a nonelectrolyte. (K, for water is 0.51°C kg/mol.) Boiling point- Submit Answer Try Another Version 5 item attempts remaining

0.0519 kg of biphenyl (C₁₂H₁₀) is dissolve in benzene (C₆H₆) to create a solution with a total volume of 350.0 mL. (Assume the change in volume is negligible)   What intermolecular forces are shared between biphenyl and benzene? If the boiling point of pure benzene is 80.1 °C, then what would be the boiling point of this solution in °C? (Kb for benzene is 2.53 °C/m and the density of benzene is 0.877 g/mL) If the vapor pressure of pure benzene is 24.4 kPa at 40.0 °C, then what will the vapor pressure of the solution be in kPa? (Consider biphenyl to be nonvolatile and the density of benzene is 0.877 g/mL) What would be the osmotic pressure (in atm) of this solution at 40.0 °C? Assume the density of the solution is the same as benzene, 0.877 g/mL.