1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (N) 0.0000 0.0019 0.000 0.0000 4364 13.092 00254 0.0762 0.1270 0.0057 21.819 0.0095 30.547 0.1778 32.729 0.7620 34.911 3.0480 30.01 Rigid Plate Cylindrical Alloy - Steel casement Figure 1 Section view of the steel casement encapsulating the eylindrical alloy

The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 151 kN. - Length of the specimen is 23 mm.  - The yield strength is 79 kN/mm2.  - The percentage of elongation is 45 %. Determine the following  (i) Diameter of the specimen,  ii) Final length of the specimen,  iii) Stress under an elastic load of 17 kN,  iv) Young's Modulus if the elongation is 2.4 mm at 17 kN  and  (v) Final diameter if the percentage of reduction in area is 24 %.  THE QUESTION IS :  FIND THE Final Diameter of the Specimen after Fracture (in mm)????

Only answer the graph portion, the image of the bolt is invade the area or length is relevant

1. Ductile materials are tougher than brittle ones II. Tensile tests are not used when the material is brittle III. Brittle materials reach much higher ultimate stresses in tension than in compression Which statement(s) given above is/are true?

A tensile test specimen of stainless steel alloy having a diameter of 0.495 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the proportional limit. Stress (ksi) 40 30- 20 10- 0- 0.0 0.0 Upper scale 0.020 0.002 22 ksi O 15 ksi E 19 ksi O 10 ksi 13 ksi Lower scale- 0.040 0.060 0.080 0.100 0.004 0.006 0.008 0.010 Strain (in./in.) 0.120 0.012

1) Draw (using a normal graph paper) a conventional stress-strain diagram for ANY metallic material (e.g. steel, aluminium, copper, brass, iron, tungsten). The diagram should be as accurate as possible using a suitable scale (e.g. 1cm: 10 N). 2) Calculate the Modulus of Elasticity, Modulus of Toughness and Modulus of Resilience for the material from the stress-strain diagram. Show your calculations in detail on a separate A4 piece of paper.

Given the following stress-strain graph:a. is the modulus of elasticity of "A-514" greater, less or equal to the one of "A-572"?b. from the previous question, make an estimatio for both of them, check that the graphic comes in %c. If we were to test these materials in a universal tension equipment, which one would withstand more load?d. If we were to test these materials in a universal tension machine, which one would elongate the most before fracturing? would elongate the most before fracturing?  e. Of the 6 materials shown, do any behave as brittle materials?  f.

diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the fracture 2.00 in. The data is listed in the table. Plot the stress-strain 8-1. A tension test was performed on a steel specimen n original diameter of 0.503 in. and gage length of PROBLEMS *84. origi the f having an for t and stress. Use a scale of 1 in. Dodraw the elastic region, using the same stress scale but a 20 ksi and 1 in. = 0.05 in./in. strain scale of 1 in.= 0.001 in./in. Load (kip) Elongation (in.) 0. 0. 0.0005 0.0015 1.50 4.60 8.00 11.00 0.0025 0.0035 0.0050 11.80 11.80 0.0080 0.0200 12.00 16.60 0.0400 0.1000 0.2800 20.00 21.50 19.50 18.50 0.4000 0.4600 Prob. 8-1

TelkomSA E estion CALCULATIONS 4.1 Using the given pulley radius and the weight values, calculate the torque applied to the specimens. ← 4.2 Calculate the theoretical angle of twist. 4.3 Calculate the experimental angle of twist for the specimen by using the dial gauge readings and the lever distance to where the dial gauge makes contact. 4.4 Calculate the maximum torsional shear stress and compare the values to the shear stress limits of the material and discuss. 4.76% Rod - Experiment T mass. displacement cog 2009 300g 400g soog Torsion of a Diameter of pulley - 180, 4 mm Length of rad 304mm Diameter of rod at Centre Point - [6,7mm). Measure distance of lever - 19,52 mm Aluminum Solid rod. displacement mass 9,11 mm 9,23 mm 2,34 mm Q. 47 mm g s S8 mm 11:57 3 O

answer e and f only please..