1. A steel rod is subjected to tension force (diameter: 30 mm) is made of annealed AISI 1015 steel. Yield strength of the annealed AISI 1015 steel is 386 MPa. (a) If the test specimen yielded when it was subjected to tensile force P, calculate P. yielding if the applied tensile force P is 1,200 kN. (b) Calculate safety factor against 30mm

1. A steel rod is subjected to tension force (diameter: 30 mm) is made of annealed AISI 1015 steel. Yield strength of the annealed AISI 1015 steel is 386 MPa. (a) If the test specimen yielded when it was subjected to tensile force P, calculate P. yielding if the applied tensile force P is 1,200 kN. (b) Calculate safety factor against 30mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

*O llAsiacell Strength of m. -> 02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile test under maximum load 66KN with elongation 7.5mm, and the yield load of this specimen is 15KN with elongation 2.4mm. Calculate: 1- The engineering ultimate stress (ultimate tensile strength), and engineering strain at this point. 2- The engineering stress and strain at yield point. 3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. Q3: The yoke-and-rod connection is subjected to a tensile force of 15 kN. Determine the average normal stress in each rod and the average shear stress in the pin A between the members. Finally, find the shear strain in pin A. Take G teef 75GPA 40 mm 15 kN, 30 mm 30 mn 15 kN 04: In figure as shown below, assume that a 35mm diameter rivet joint the…
yields under a load of 8KN; it attains a max load of 15KN and breaks finally A tensile test is carried out on a bar of mild steel of diameter 20mm. The bar Еxample at a load of 7KN. Estimate yP (i) The tensile stress at the yield point (ii) The ultimate tensile test ii. Max loa (iii) The average stress at the breaking point if the diameter of neck is Omm.
A tensile test was conducted on a mild steel& the following data was obtained as follows. Diameter of the steel bar = 3 cm,Gauge length of the bar = 20 cm. Load at elastic limit = 250 kN . Extension at a load of 150kN = 0.21 mm . Maximum load = 380 kN . Total extension = 60 mm . Diameter of the rod at failure = 2. 25 cm Determine: (a) Young’s modulus (b) stress at elastic limit (c)the percentage of elongation (d) Percentage decrease in area.
A sample test rod made of a ferrous material of 0.5 in. diameter was tested for tensile strength with the gauge length of 2.5 in. The following observations were recorded: Final length = 3.15 in; Final diameter = 0.275 in; Yield load = 7650 lb. and Ultimate load = 10375 lb. (a) Calculate: 1. yield stress, 2. ultimate tensile stress, 3. percentage reduction in area, and 4. percentage elongation. (b) What specific material, if any, is similar to this tested rod? Refer to AT7 and AT8. (c) This same material is then used as a tension member 55 inches long and is subjected to a maximum load of 6000 lb, repeated but not reversed. (d) Solve part (c) if the total elongation is not to exceed 0.025 in.? 1. %3D
2. A steel of rotating-beam test specimen has an ultimate strength of 1100Mpa. Estimate the fatigue strength of the specimen corresponding to a life of 150k cycles of stress reversal.
The Highest load sustained druing an uniaxial tensile testing experiment is 7,500lb. If the original cross section has a diamter of 0.25in, what is the ultimate tensile strength? (please also make a drawing)
Force P and length change AL data are given in table below for the initial portion of a tension test on 7075-T651 Al alloy. The diameter before testing was 9.07 mm., and the gage length Linitial for t length change measurement was 50.8 mm. Determine the yield strength with offset limit, and %total elongation. P, kN AL mm 7.22 14.34 0.0839 0.1636 21.06 0.241 26.8 0.308 31.7 0.380 34.1 0.484 35.0 0.614 36.0 0.924 36.5 1.279 36.9 1.622 37.2 1.994
2. A tensile test is performed on a bar of Dural (an aluminium alloy) of diameter 15 mm. The bar yields under a load of 30 kN and reaches a maximum load of 46 kN. Estimate the tensile yield stress and tensile strength of Dural
Mild Steel is tested in the laboratory. The data obtained are:Length of Specimen = 320 mmDiameter of Specimen = 30 mmElongation under a load of 20 kN = 0.055 mmLoad at Yield Point = 130 kNMaximum Load = 210 kNLoad at fracture = 115 kNLength of Specimen at failure = 380 mmDiameter of Specimen at failure = 17.5 mm Calculate: (1).Young’s Modulus (2). Yield Stress (3). Ultimate Stress
QI (a) A tensile stress is to be applied along the axis of a cylindrical steel rod that has a diameter of 7.5 mm. Given the Poisson's ratio, v is 0.30 and the modulus of elasticity, E of the steel is 207 GPa. Determine the magnitude of the load required to produce a 2.5 x10³ mm change in diameter if the deformation is entirely elastic. (b) Referring to the tensile test data tabulated in Table 1, answer the following questions: i. Select with justification the material that will experience the greatest percent reduction in area. ii. Select with justification which material is the strongest. Table 1. Tensile stress-strain data for several hypothetical metals Material Yield Tensile Strain at Fracture Elastic Strength Strength Fracture Strength Modulus (МРа) (MPa) (MPa) (GPa) A 310 340 0.23 265 210 100 120 0.40 105 150 C 415 550 0.15 500 310 D 700 850 0.14 720 210 E Fracture before yielding 650 350
A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile test under maximum load 66KN with elongation 7.5mm, and the yield load of this specimen is 15KN with elongation 2.4mm. Calculate: 1- The engineering ultimate stress (ultimate tensile strength), and engineering strain at this point. 2- The engineering stress and strain at yield point. 3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. any four point sir
1. A steel of rotating-beam test specimen has an ultimate strength of 1600Mpa. Estimate the life of the specimen if it is tested at a completely reversed stress amplitude of 900MPA. Hint: You can either extrapolate the curve of f vs. Sut, or use the equation derived on P10 to estimate the value of f.