1- The mercury present in a sample with a mass equal to 0.8142 g was precipitated with an excess of paraperiodic acid (H5I06) according to the reaction below: 5 Hg2* + 2 H5lO6 - Hg5(106)2 + 10 H* The precipitate was filtered, washed free of precipitating agent, dried and weighed to give 0.4114 g. Calculate the % of Hg and of Hg2C12 in the sample. Data: Hg = 200.59 H = 1.008 Cl = 35.45 | = 126.90 %3D O = 16.00 %3D

A solution is initially 0.10 M in Mg2*(aq) and 0.10 M in Fe2* Mg(OH)2 first precipitates? Ksp (Mg(OH)2) = 6.0 x 10-10; Ksp(Fe(OH)2) = 7.9 x 10-16 your answer in E-notation, rounded to 2 significant digits. *(aq). A solution of NaOH is slowly added. What is the concentration of Fe2+ when %3D Provide

Mark and John, two vinegar enthusiasts, are each tasked to determine the acetic acid content of their respective vinegar concoctions by titration. First, a 1 M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol) standard that is 99.4% pure. In the process, 0.540 g KHP was found to require 2.80 mL of the KOH solution to completely react up to the phenolphthalein endpoint. Then, Mark and John both prepared their samples by taking 10.0-mL aliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant and indicator, Mark’s vinegar required 18.60 mL of the standardized titrant to reach the endpoint, while John’s vinegar required 16.50 mL of the same titrant to reach the same endpoint. Question: What is the acetic acid concentration of Mark’s and John’s vinegar in molarity given that the Concentration of KOH is 9386 M?

O Microsoft O shift V A chemistry student weighs out 0.0608 g of formic acid (HCHO₂) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1400M NaOH solution. OCHEMICAL REACTIONS Determining the volume of base needed to titrate a given mass... Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits. W Microsoft Microsoft 6.52.210... tab esc caps lock mL control Explanation ! 1 (8) Q A Check N © 2 W S #3 X T option command E x10 X D NOV 14 $ 4 C R S F do L % 5 V T G tv ♫ 6 MacBook Pro 9 Y & 7 H Ⓒ2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility U 8 1 9 BN M A O J K O O JOD 05 L H W P > { I command option DOCX + 11 ? | 1 9 OC

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A solution contains 5.54x10 3 M sodium hydroxide and 1.26x10² M sodium sulfide. Solid iron(III) nitrate is added slowly to this mixture. What is the concentration of sulfide ion when hydroxide ion begins to precipitate? [sulfide] = M Submit Answer Retry Entire Group 7 more group attempts remaining

esc Fr 2 What mass of precipitate is formed when 100. mL of 0.300 M NaCl reacts with 100. mL of 0.150 M Pb(NO3)? Round your answer to 3 significant digits. 55°F Clear 1 F1 B.D F2 @ 2 F3 3 E F4 LA 4 x10 Q Search F5 X % 5 S F6 C A 6 F7 © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibil B 8 & 7 F8 * ос F9 DELL prt sc F10 home Submit Assignment F11 A end F12 insert + 5/

Hand written solution is not allowed and no answer from the chat gpt will dislike

is silve 0.10 ANO E) 4.26 x 10-17 M 16) A solution containing AgNO3 is mixed with a solution of NaCl to form a solution that is 0.10 M in AgNO3 and 0.075 M in NaCl. What will happen once these solutions are mixed? Ksp (AgCI) = 1.77 × 10-10 A) Silver chloride will precipitate out of solution, leaving an unsaturated solution of AgCl. B) Nothing will happen since the molar solubility of AgCl is higher than the solution concentrations. 0.075 Nac! Silver chloride will precipitate out of solution, leaving a saturated AgCl solution. D) Nothing will happen since NaCl and AgNO3 are both soluble compounds. E) There is not enough information to say anything about this solution. Ksp Ag Cl 1.77 × 10-10 16)

9. A 50.0 mL solution of acetic acid (CH3COOH) was titrated. In the process 35 mL of a 1.00 M NaOH standard were consumed. find the molarity of the acetic acid. If the density of the acetic acid solution is 1.08 g/mL, calculate the % acetic acid in the sample.                               CH3COOH + NaOH CH3COONa + H2O