ma12. 3.000 g BaCl₂.H₂O (molar mass=244.263 g/mol) was added to asolution of 100 mL of 0.050 M Na₂CO3.BaCl₂ (aq) + Na₂CO3 (aq) → BaCO3 (s) + 2NaClKsp for BaCO3 = 1.1 x 10-15Calculate the concentration of CO32 in the resulting solution.a) 5Mb) 0.050 Mc) 0.072 Md) 1.5 x 10-¹3 Me) 1.5 x 10-¹4 M

The question is based on the concept of solubility product principle. It that states that when a…

ma 12. 3.000 g BaCl₂.H₂O (molar mass=244.263 g/mol) was added to a solution of 100 mL of 0.050 M Na₂CO3. BaCl₂ (aq) + Na₂CO3 (aq) → BaCO3 (s) + 2NaCl Ksp for BaCO3 = 1.1 x 10-¹5 Calculate the concentration of CO32 in the resulting solution. a) 5M b) 0.050 M c) 0.072 M d) 1.5 x 10-¹3 M e) 1.5 x 10-¹4 M

ma 12. 3.000 g BaCl₂.H₂O (molar mass=244.263 g/mol) was added to a solution of 100 mL of 0.050 M Na₂CO3. BaCl₂ (aq) + Na₂CO3 (aq) → BaCO3 (s) + 2NaCl Ksp for BaCO3 = 1.1 x 10-¹5 Calculate the concentration of CO32 in the resulting solution. a) 5M b) 0.050 M c) 0.072 M d) 1.5 x 10-¹3 M e) 1.5 x 10-¹4 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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