1 II 1 2 a) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?

1 II 1 2 a) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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1. Please consider the following pedigree. I 1 2 II 1 a) Assume that colour is controlled by a single sex-influenced gene where orange is expressed preferentially in females. Individuals I-1 and I-2 are homozygous for orange and blue respectively. Which individual/s in generation II will be blue? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be orange?
a) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?
a. In Drosophila, crosses between F1 heterozygotes ofthe form A b / a B always yield the same ratio ofphenotypes in the F2 progeny regardless of the distance between the two genes (assuming completedominance for both autosomal genes). What is thisratio? Would this also be the case if the F1 heterozygotes were A B / a b? (Hint: Remember that inDrosophila, recombination does not take placeduring spermatogenesis.)b. If you intercrossed F1 heterozygotes of the formA b / a B in mice, the phenotypic ratio among the F2progeny would vary with the map distance betweenthe two genes. Is there a simple way to estimate themap distance based on the frequencies of the F2phenotypes, assuming rates of recombination areequal in males and females? Could you estimatemap distances in the same way if the mouse F1heterozygotes were A B / a b?
IN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.
1. The allele G for yellow stigma is completely dominant to green (g). Supposingtwo strains of autotetraploid plants are available and their genotypes are as follows:GGgg – in this plant the gene is close to the centromereGggg – in this plant the gene is far from the centromere If these two plants are crossed:a) provide the gametes that can be obtained from the two plants;b) provide the genotypic and phenotypic ratios of the offspring. 2. Consider the illustration below. Diagram the configuration you would observe at Anaphase I if crossing-over happens within the inversion. (IMAGE ATTACHED)
A mutant sex-linked trait called “notched” (N) is deadly in Drosophila when homozygous in females. Males who have a single N allele will also die. The heterozygous condition (Nn) causes small notches on the wing. The normal condition in both male and females is represented by the allele n. a) Indicate the phenotypes of the F1 generation from the following cross: XNXn x XnY b) Explain why dead females are never found in the F1 generation no matter which parents are crossed. c) Explain why the mating of female XNXn and a male XNy is unlikely.
In Drosophila melanogaster, red eyes are dominant over white and the variation for this characteristic is on the X chromosome. Vestigial wings (v) are recessive to normal (V) for an autosomal gene. Predict the appearance of offspring of the following crosses: XW/Xw V/v×Xw/Y v/v, Xw/Xw V/v × XW/Y V/v.
11. In Drosophila, three autosomal genes have the following map 5 m.u. 10 m.u. b + When a+ b+ c+ abc females are crossed to a bclabc males, how many flies of the phenotype a+ b c+ is expected among 1000 progeny assuming interference of 60%? A) 1 B) 2 C) 5 D) 3 E) 10
Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
19) In Drosophila fruit flies, the gene controlling bristle length is X-linked. Wild type flies have long bristles; short bristles is a recessive trait. You cross a long-bristled female fly to a short-bristled male fly. All the F1 progeny have a wild type phenotype. Next, you cross the F1 flies to produce an F2 generation. If there are a total of 200 F2 flies, how many of the F2 females are expected to have short bristles? V/100 Wild type fruit flies have grey bodies and straight wings. Yellow bodies and curly wings are both recessive phenotypes. The body color gene is X-linked; the wild type allele is designated XY+. The wing shape gene is autosomal; the wild type allele is designated C+. You cross a pure breeding yellow-bodied, curly-winged female with a grey-bodied, straight-winged male to produce an F1 generation. Use this information to answer questions X-Y below. You cross two F1 flies to produce an F2 generation. You select a female F2 fly that is phenotypically wild type. What…
In domesticated cats, the following are Independently assorting: 6. Normal ears (T) is dominant to tufted ears (t); Curved whiskers (C) is dominant to straight whiskers (c); The presence of six toes (S) is dominant to five toes (s); Gene for hair length is an X-linked codominant. The three phenotypes for hair length are long (XHXH), medium (X"X*), and short (X"Xh); medium is the heterozygous condition. Given two parents: TtccSSXHXh x TtCcSsXHY a) How many different gametes could be formed in the female cat with respect to these four traits? b) How many different phenotypes are possible in the offspring from this mating?
EC1. In drosophila the cw (curly wings) gene and eb (ebony body) genes are found on the same chromosome 20 map units apart. A cross was made between an ebony bodied parental strain and a curly winged parental strain and the F1’s were test crossed. a) What are the genotypes of the parental strains? b) What are the genotypes of the F1’s? c) What is the genotype of the tester strain? d) What progeny phenotypes and genotypes do you expect, and in what proportions? For phenotypes use the mutant phenotype for any that the flies have, and wild-type if they have none. EC2. Here is a tetrad produced by mating a H Y strain to an h y strain. a) What is the tetrad type? b) What has recombined with what? EC3. In corn, a dihybrid for the recessive genes a and b is test-crossed. The distribution of the phenotypes is as follows: A B 122A b 118a B 81a b 79 a) Do the genes appear to be sorting independently? Look at map units here. b) Test your hypothesis with a chi-squared test.