1 A + 2 B → 2 C Calculate the equilibrium constant (K) for the following reaction at 1000. K, using this information: A and B are placed in a flask and at the beginning of the reaction [A] is 8.95 M and [B] is 6.21 M. After the reaction has reached equilibrium,[B] is 1.94 M. Please ignore significant figures for this problem.

Consider the equilibrium system described by the chemical reaction below. If the partial pressures at equilibrium of NO, Cl2, and NOCI are 0.095 atm, 0.171 atm, and 0.28 atm, respectively, in a reaction vessel of 7.00 L at 500 K, what is the value of Kp for this reaction? 2 NO(g) + Cl2(g) = 2 NOCI(g)

3 A + 2B 1 C Calculate the equilibrium constant (K) for the following reaction at 1000. K, using this information: A and B are placed in a flask and at the beginning of the reaction [A] is 6.87 M and [B] is 6.38 M. After the reaction has reached equilibrium, [C] is 1.47 M. Unfortunately, significant figures cannot be taken into account here, so please ignore them this time. 119.84085 0.00132 0.00011 0.03354 0.00834 1 1 1

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.400 M , [B] = 1.40 M , and [C] = 0.300 M. The following reaction occurs and equilibrium is established: %3D %3D A + 2B = C At equilibrium, [A] = 0.270 M and [C = 0.430 M. Calculate the value of the equilibrium constant, K. Express your answer numerically. • View Available Hint(s) ΑΣφ Kc =

The equilibrium constant for the following reaction is 67.6 at 232 °C. PCI 3(g) + Cl₂(g) PCI5(g) K = 67.6 at 232 °C Calculate the equilibrium constant for the following reactions at 232 °C. (a) PCI5(g) PCl3(g) + Cl₂(g) K= (b) 2 PCI5(g) 2 PCI3(g) + 2 Cl₂(g) K=

Consider the following equilibria at a given temperature: ½Nalg) + J½O>(g) = NO(g) K= 6.45 x 10°, NO (g) + 1½Brz(g) = NOB((g) K= 1.40 Determine the value of the equilibrium constant for the following reaction at the same temperature: %N(g) + ½Ozlg) + ½Br2(g) = NOBr(g) OA 583 x 107 O B.3.36 x 10-18 OC4.17x 107 OD.6.45 x 10 OE 9.03 x 10

A student ran the following reaction in the laboratory at 591 K:COCl2(g) CO(g) + Cl2(g)When she introduced COCl2(g) at a pressure of 0.380 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of Cl2(g) to be 0.247 atm.Calculate the equilibrium constant, Kp, she obtained for this reaction.

A chemical engineer is studying the following reaction: H₂(g) + Cl₂(g) → 2 HCl(g) At the temperature the engineer picks, the equilibrium constant K, for this reaction is 0.83. The engineer charges ("fills") three reaction vessels with hydrogen and chlorine, and lets the reaction begin. He then measures the composition of the mixture inside each vessel from time to time. His first set of measurements are shown in the table below. Predict the changes in the compositions the engineer should expect next time he measures the compositions. reaction vessel A C compound H₂ Cl₂ HCI H₂ CL₂ HCI H₂ CL₂ HCI pressure 4.00 atm 1.97 atm 3.36 atm 4.27 atm 2.82 m 3.84 atm 1.81 atm 3.69 atm expected change in pressure 1 increase O decrease decrease Of increase Of increase Ⓒ↓ decrease Of increase O decrease decrease O1 increase Ot increase O decrease Of increase O decrease Of increase O decrease decrease Of increase O (no change) (no change) O(no change) (no change) (no change) (no change) (no change) (no…