= 0.6 V, Vtp tn For the circuit of Fig. 7.25, let VDD = Vss=2.5 V. = -0.6 V, all channel lengths = 1 um, k = 200 μA/V², k = 80 μA/V², and λ = 0. For IREF = 10 μA, find the widths of all transistors to obtain 12 = 60 μA, 3 = 20 µA, and I5 = 80 µA. It is further required that the voltage at the drain of Q₂ be allowed to go down to within 0.2 V of the negative supply and that the voltage at the drain of Q5 be allowed to go up to within 0.2 V of the positive supply. IREF wwww R + Vast VDD A V SG5 24|1 125 √13 Q3 -Vss

= 0.6 V, Vtp tn For the circuit of Fig. 7.25, let VDD = Vss=2.5 V. = -0.6 V, all channel lengths = 1 um, k = 200 μA/V², k = 80 μA/V², and λ = 0. For IREF = 10 μA, find the widths of all transistors to obtain 12 = 60 μA, 3 = 20 µA, and I5 = 80 µA. It is further required that the voltage at the drain of Q₂ be allowed to go down to within 0.2 V of the negative supply and that the voltage at the drain of Q5 be allowed to go up to within 0.2 V of the positive supply. IREF wwww R + Vast VDD A V SG5 24|1 125 √13 Q3 -Vss

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

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Homework
The current flowing into the collector lead of a certain bipolar junction transistor (BJT) is measured to be 1 nA. If no charge was transferred in or out of the collector lead prior to t = 0, and the current flows for 1 min, calculate the total charge in nC which crosses into the collector.