. Among adults with Turner syndrome, it has beenfound that a very high proportion are genetic mosaics.These are of two types: In some individuals, themajority of cells are XO, but a minority of cellsare XX. In other Turner individuals, the majorityof cells are XO, but a minority of cells are XY.Explain how these two patterns of somatic mosaicscould arise.

. Among adults with Turner syndrome, it has beenfound that a very high proportion are genetic mosaics.These are of two types: In some individuals, themajority of cells are XO, but a minority of cellsare XX. In other Turner individuals, the majorityof cells are XO, but a minority of cells are XY.Explain how these two patterns of somatic mosaicscould arise.

Name: . Among adults with Turner syndrome, it has beenfound that a very high
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Description: . Among adults with Turner syndrome, it has beenfound that a very high proportion are genetic mosaics.These are of two types: In some individuals, themajority of cells are XO, but a minority of cellsare XX. In other Turner individuals, the majorityof

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

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In individuals affected by cystic fibrosis, salt crystals may appear afterperspiration dries up. In addition, the disease causes respiratory disorderswhich can be both debilitating and lethal. It occurs in individuals homozygousfor the recessive gene. Two normal parents had a daughter with thesymptoms of this disease, and a normal son who marries a normal womanwith an afflicted A test (salt concentration in perspiration of heterozygotes ishigher than normal) disclosed that both are indeed carriers of the gene. If thefirst child born to the mating in (b) was defective, what is the probability thatthe 2nd child would also be defective?Express answer in fraction form
а. What type of inheritance is shown in the pedigree? II 2 II 1 2 4 IV Identify the genotypes of the following individuals: III- 2 b. |-1 Il- 2 III-4 IV-1 + v Paragraph В I
The karyotype of a young girl who is affected with familialDown syndrome revealed a total of 46 chromosomes. Her olderbrother, however, who is phenotypically unaffected, actually had45 chromosomes. Explain how this could happen. What wouldyou expect to be the numbers of chromosomes in the parents ofthese two children?
1. Choose the phrase from the right column that best fitsthe term in the left column.a. cytoplasmicsegregation1. transmission of genes through maternalgamete onlyb. heteroplasmic 2. cell that has mtDNAs or cpDNAs all of onegenotypec. homoplasmic 3. having gametes of similar sized. maternalinheritance4. a cell with a mixture of different mtDNAsgenerates a daughter cell with only one kinde. uniparentalinheritance5. a specific fraction of wild-type organellarDNAs is required for a wild-type phenotypef. isogamous 6. cell with mtDNAs or cpDNAs with differentgenotypesg. threshold effect 7. transmission of genes through either amaternal or a paternal gamete, but not both
The XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?
. A diploid strain of yeast was made by mating a haploidstrain with a genotype w−, x−, y−, and z− with a haploidstrain of opposite mating type that is wild type for thesefour genes. The diploid strain was phenotypically wildtype. Four different X-ray-induced diploid mutantswith the following phenotypes were produced fromthis diploid yeast strain. Assume a single new mutation is present in each strain.Strain 1 w− x+ y− z+Strain 2 w+ x− y− z−Strain 3 w− x+ y− z−Strain 4 w− x+ y+ z+When these mutant diploid strains of yeast go throughmeiosis, each ascus is found to contain only two viablehaploid spores.a. What kind of mutations were induced by X-rays tomake the listed diploid strains?b. Why did two spores in each ascus die?c. Are any of the genes w, x, y, or z located on thesame chromosome?d. Give the order of the genes that are found on thesame chromosome
Ehler-Danlos syndrome is a rare disorder caused by a mutation ina gene that encodes a protein called collagen (type 3 A1). Collagenis found in the extracellular matrix that plays an important role inthe formation of skin, joints, and other connective tissues. Peoplewith Ehler-Danlos syndrome have extraordinarily flexible skin andvery loose joints. The following pedigree contains several individualsaffected with this syndrome, shown with black symbols. Basedon this pedigree, does the syndrome follow autosomal recessive,autosomal dominant, X-linked recessive, or X-linked dominantinheritance? Explain your reasoning.
. An allotetraploid species has a genome composed oftwo ancestral genomes, A and B, each of which havea basic chromosome number (x) of seven. In thisspecies, the two copies of each chromosome of eachancestral genome pair only with each other duringmeiosis. Resistance to a pathogen that attacks the foliage of the plant is controlled by a dominant allele atthe F locus. The recessive alleles Faand Fbconfersensitivity to the pathogen, but the dominant resistancealleles present in the two genomes have slightly different effects. Plants with at least one FAallele areresistant to races 1 and 2 of the pathogen regardlessof the genotype in the B genome, and plants with atleast one FBallele are resistant to races 1 and 3 of thepathogen regardless of the genotype in the A genome.What proportion of the self-progeny of an FA Fa FB Fbplant will be resistant to all three races of the pathogen?
Ehler-Danlos syndrome is a rare disorder caused by a mutation ina gene that encodes a protein called collagen (type 3 A1). Collagenis found in the extracellular matrix that plays an important role inthe formation of skin, joints, and other connective tissues. Peoplewith Ehler-Danlos syndrome have extraordinarily flexible skin and very loose joints. The pedigree below contains several individualsaffected with this syndrome, shown with black symbols. Based onthis pedigree, does the syndrome appear to follow autosomalrecessive, autosomal dominant, X-linked recessive, or X-linkeddominant inheritance? Explain your reasoning.
3. An inversion heterozygote has the following inverted chromosome: Centromere )))))))))))) A B JI HGF ED CKLM Inverted region What would be the products if a crossover occurred between the genes F and E on the inverted chromosome and the normal chromosome?
Neurospora of genotype a + c are crossed withNeurospora of genotype + b +. (Here, + is shorthandfor the wild-type allele.) The following tetrads areobtained (note that the genotype of the four sporepairs in an ascus are listed, rather than listing alleight spores):a + c a b c + + c + b c a b + a + ca + c a b c a + c a b c a b + a b c+ b + + + + + b + + + + + + c + + ++ b + + + + a b + a + + + + c + b +137 141 26 25 2 3a. In how many cells has meiosis occurred to yieldthese data?b. Give the best genetic map to explain these results.Indicate all relevant genetic distances, both betweengenes and between each gene and the centromere.c. Diagram a meiosis that could give rise to oneof the three tetrads in the class at the far right inthe list
Name: 2. Some ladybugs have 10 black spots on their shells and some have 4. When true breeding 10 spot individuals are crossed with true breeding 4 spot individuals, the offspring have 7 spots. a. Propose two distinct explanations for this finding. Explain the nature of spot inheritance in each case. D. rew bacteria erred them figure above would of14N7 then ely 2 moldon omrod abitqaq ratlsmmem sge of delw toiisoibom s s neu not oomod aid to soubnup ogusl onomod odi to slevel ismon oouborg o o consu ud od souboini bluow uoy dairlw yd za00oq sdi mialex b. Propose an experiment that would distinguish between these possibilities. sor proieins