Concept explainers
The simple pendulum is a mechanical device that illustrates several concepts about forces and motion. The simple pendulum uses a string or cord to suspend a mass at some length from a pivot point. The mass is called the bob and when displaced from rest, will move in
The last thing this experiment will show is that the relationship between the length of the pendulum and the pendulum’s period (the time for one cycle) can be described by the statement: the period of a pendulum is directly proportional to the square root of the length of the pendulum. Or that the length of the pendulum is directly proportional to the square of the pendulum’s period. Three different lengths of string will be used to measure the period of the pendulum and a graph will be made of the period’s time squared and the length.
MECHANICS OF A SIMPLE PENDULUM Any simple pendulum can be described by the relationship between the pendulum’s period of oscillation, the length of the pendulum, and the gravitational acceleration. This relationship is given by the equation where T is the time in seconds for one cycle, L is the length of the pendulum from the pivot point to the center of mass of the bob, and g is the acceleration from gravity. Notice that there is no mass variable in this equation, meaning that mass has no effect on the motion of a pendulum. We can measure the period of the pendulum with a stopwatch, we can also measure the length of the pendulum. If we then solve the equation for g, we can determine the gravitational acceleration using a simple pendulum. Taking the equation above we can divide both sides of the equation by 2π which then gives, we can then square both sides of the equation to get rid of the radical, which gives us, we can then use the reciprocal rule to invert both sides of the equation which gives, finally we multiply both sides of the equation by L to isolate g by itself, which gives us, We will use this equation to determine g from the pendulum’s period and length.
3. A simple pendulum has a length of 30 cm. What is the pendulum’s period? Show your calculation.
4. When timing the period of the pendulum in the lab, why does timing ten cycles of the pendulum provide better accuracy than timing one cycle of the pendulum ten times?
5. Based on Newton’s Second Law, why does the mass of the suspended bob apparently have no effect on the period of a pendulum’s motion? Explain.
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps with 2 images
- A spring-mass system has a spring with spring constant k=85.0 N/m and a 650.0 gram mass on the end of the spring. The surface supporting the mass is frictionless and there is negligible air resistance. When the system is first observed (at time t = 0), the spring is stretched 13.20 cm from its natural length and the velocity of the mass is 1.90 m/s in the +x direction. 1. What is the displacement function x(t) for this motion? 2. If the spring-mass system was placed in a chamber where the air resistance has a drag constant of b = 1.40, what is the frequency of the new system, in rad/s? Round to the nearest hundredth (0.01). Justify your answer using your rationale and equations used.arrow_forwardA spring is attached to a block with a mass of 2.33 kg. The block is set on a rough horizonal surface, and you pull horizontally on the other end of the spring, steadily increasing the force. As soon as the spring stretches 0.126 m beyond its equilibrium length, you notice the block starts to move. If the spring constant is 75.8 N/m, what is the coefficient of static friction between the block and the surface?arrow_forwardA pendulum has a 10 kg bob on a string that is 2 m long. It is raised so that it forms an angle of 90 degrees with it's resting position. (It is horizontal, parallel with the ground). [I can't find a decent picture of this on the internet so ask me if you can't picture this. ] O-196 J O-20J 20 J O 196Jarrow_forward
- A car with mass 1530 kg crashes into a wall. The car’s velocity immediately before the collision was 12.6 m/s and the bumper is compressed like a spring with spring constant 1.14 × 107 N/m. What is the maximum deformation of the bumper for this collision?Answer in units of m.arrow_forwardTrue or False: As a pendulum swings through its cycle, the mass is moving fastest and has its greatest acceleration at the bottom of the swing.arrow_forwardHow do I summarize the two vectors shown?arrow_forward
- Please answer this University Physics Question.arrow_forwardAn ornament of mass 36.9 g is attached to a vertical ideal spring with a force constant (spring constant) of 51.8 N/m. The ornament is then lowered very slowly until the spring stops stretching. How much does the spring stretch?arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON