End Of Semester Lab Report

1. What new concepts or theories have you learned about after completing this lab activity?

When the pH is not at its optimum, the differing pH's will disrupt the bonding between the R groups of the amino acid causing its structure and the shape of the activation site to change

1. Capillary action will draw the salt solution up the paper. As it passes through the dots, it will begin to separate the dyes. When the salt water is 1/4 inch (0.5 cm) from the top edge of the paper, remove it from the glass and place it on a clean, flat surface to dry.

The 2nd half for the gel is our experiment compared to Anderson group 6. The 1st layer in all 3 pictures is the bound dye, the 2nd layer is the free dye.

I am unable to answer this question because I don’t think I have enough information. This is asking for exact values and I don’t have the data to answer it. I maybe overlooking the answer but I am unable to figure this out.

If a sample’s Rf is lower, that means that it remained closer to the stationary phase. In both variations of the experiment, red dye #40 remained the closest to the stationary phase (on average). Therefore, the red dye #40 had the lowest rate of flow value. The intermolecular forces of the red dye are responsible for its low distance traveled. The molecules of the chromatography paper have strong intermolecular bonds that are highly polar. The red dye is attracted to the paper because of their similar characteristics. The negative and positive ends of both the paper molecules and the red dye #40 molecules attract to each other. It is extremely difficult for the isopropyl alcohol and the sodium chloride solutions to interfere with the bonds of paper and ready dye #40, as a result, both solutions are unable to fully dissolve red dye #40. . NaCl and isopropyl alcohol have very strong intermolecular forces, but the forces of the paper’s molecule were able to attract red dye #40 because they were even

The mole is a convenient unit for analyzing chemical reactions. Avogadro’s number is equal to the mole. The mass of a mole of any compound or element is the mass in grams that corresponds to the molecular formula, also known as the atomic mass. In this experiment, you will observe the reaction of iron nails with a solution of copper (II) chloride and determine the number of moles involved in the reaction. You will determine the number of moles of copper produced in the reaction of iron and copper (II) chloride, determine the number of moles of iron used up in the reaction of iron and copper (II) chloride, determine the ratio of moles of iron to moles of copper, and determine the number of atoms and formula units involved in

For part one of this experiment, I only experienced separation of colors with the green and brown M&M’s, along with the yellow food coloring. The green M&M separated into yellow and blue, with blue travelling farther up the paper. It is not surprising that green separated into blue and yellow because those are the primary colors that make up green. The brown M&M separated into red and orange, with the orange travelling farther up the paper. Finally, the yellow food coloring separated into yellow and red, with yellow travelling farther up the paper. This could be because it was such a concentrated, small amount of food coloring. The colors that didn’t travel very far up the paper, such as orange and brown, are probably less soluble than the others, like blue and green.

Note: Your prelab/lab report is to be done in your carbon copy lab notebook (sold in FIU bookstore)

5. The final result when all the dye emerges at the downstream side is shown in Figure 1.

Title: Principle and Practice of Gel Electrophoresis. Aim: To determine the unknown dyes in Unknown Mix 1 and Unknown Mix 2 from the four known dye samples using gel electrophoresis.

1. The samples were very clear in what they were portraying and was very easy to understand. I tried my best to follow the references and to make the experiment running as smooth as it seemed to be in the reference material.

As the solvent moves past the spotted mixture, two opposing forces created by the solvent and the adsorbent influence the mixture. Each component can either dissolve in the mobile solvent or remain adsorbed to the stationary adsorbent. This process generates an equilibrium, as some components are adsorbed and others are dissolved and transported with the solvent until they are readsorbed further along the plate. The different tendencies of each component to comply with the subjected forces may result in a successfully separated mixture on the plate.

2. (5 pts) List and explain the names and affiliations of the various characters/stakeholders in this story – I’m looking for us to use the story to map out the complexities that are generally associated with solving public health puzzles – the stakeholders you list and explain here should apply to many of the cases we consider going forward.

Physical Adsorption- In physical adsorption, weak Vander waal’s intermolecular forces of attraction is involved between adsorbate and adsorbent. It takes place at low temperature and does not require any activation energy to overcome the weak vander waal’s forces. It is not very specific and reversible process and therefore is of much use for the separation of fluids. The application of physical adsorption has major application in the industries like hydrogen and oxygen purification.