A spherical cell with the diameter of 10uMhas a protein concentration of 20 mg/ml. Determine the number of protein molecules within the cell if the molecular weight of an average protein is 50,000 daltons (g/mol). Recall that Avogadro's number is N₁ = 6.0221367×1023 molecules/mol.
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- A spherical cell with the diameter of 10uMhas a protein concentration of 20 mg/ml. Determine the number of protein molecules within the cell if the molecular weight of an average protein is 50,000 daltons (g/mol). Recall that Avogadro's number is NA 6.0221367×1023 molecules/mol. =Protein concentration can readily be determined using the Beer-Lambert law: A = e l c where A = absorbance e = molar absorption coefficient (M-1cm-1) l = light path length (cm) c = concentration (M) If the molar absorption coefficient at 280 nm for yeast ADH is 48860 M-1cm-1 and a 10 mL solution of the protein has an absorbance at 280 nm of 0.4 (as measured by a spectrometer with pathlength 1 cm), then what is the concentration of the protein solution (in μM)? i.e. concentration = ______ μM If the molecular weight of the protein is 36849, what is its concentration in mg/mL? i.e. concentration = _______ mg/mL For each part of the question, show your calculations to arrive at your answers.2. 0.1 mL of a protein solution of concentration of 7 mg/mL was diluted to a total volume of 4.0 mL with water (i.e. 0.1 mL of the solution was added to 3.9 mL of water). 3 mL of this solution was then mixed with 27 mL of water. What is the concentration of the diluted protein solution? Space to show your workings:
- The A280 of a protein sample loaded onto a gel was determined to be 0.767 (1.00 cm path length, after subtracting the blank). The total volume of this sample was 428 µL. 19.0 µL of this protein sample was mixed with 19.0 µL of 2X laemalli sample buffer and then 12.0 µL of the entire sample was loaded into the gel and electrophoresed. Calculate the amount of protein that was loaded into the gel (in µg).Give only typing answer with explanation and conclusion You want to make 94 µL of the diluted Cell-Free extract for estimation of total protein. To do this, how much water will you add to the correct volume of the undiluted cell-free extract? Note: Cell-free extracts will need to be diluted 1:25 in water.A protein required 6.8 min to travel 82 cm to the detector in a 96 cm -long capillary tube with 25.4 kV between the ends. Find the apparent electrophoretic mobility. How many femtomoles of 2.4 μM protein are injected electrokinetically into a 50 μm diameter capillary at 5.0 kV for 3.0 sec. if the sample has half of the conductivity of the background electrolyte.
- 6-73 In each case, tell which side (if either) rises and why. The solvent is water. A A Osmotic membrane (a) 1% glucose (b) 0.1 M glucose (c) 1 M NaCl (d) 1 M NaCl (e) 3% NaCl (f) 1 M NaBr (B) B 5% glucose 0.5 M glucose 1 M glucose 1 M K₂SO4 3% KC1 1 M KC1Does this calculation look correct? My goal isto have a target mass of 10 µg of my protein with a total volume of 30 µl. Protein was measured and found to have a concentration of at 308.35 µg/ml Recall, mass = concentration * volume 10 µg = 308.35 µg/ml * V V = 0.01 mg/ 0.30835 mg/mL = 0.032430679 mL = 32.43067942 µL Note: cannot measure this amount; two dilutions required. Dilute by 1/40: measure 2.5 µl of protein at 0.30835 µg/µl and add it to 97.5 diluent to prepare a solution of protein at 7.71 mg/ml. This diluted sample will be used further. Mass = concentration * volume 10 µg = 7.71 mg/ml * V V = 0.01 mg/ 7.71 mg/ml = 1.3 µL Therefore, will measure 1.3 µl of protein at 7.71 mg/ml and add it to 28.7 µl of diluent.Polymer beads (resin) made of DEAE (diethylaminoethyl) cellulose are packed in an ion exchange column. The total mass of beads in the column is 8.47 kg. On average, each bead weighs 0.0023 g and has an average of 18.4 * 10° positively charged amine groups that can adsorba negatively charged protein that passes through the column. A solution containing 2.07 mg/L of a protein is maintained at pH 6.3 and is passed through the ion exchange column at 0.215 L/min. The protein has a molecular weight of 154,000. The pk, of the amino groups on DEAE cellulose is 7.1, and the pl of the protein is 5.6. 2. A. How long can the column be operated before reaching 80% capacity (i.e., 80% of the amino groups on DEAE are bound to the protein through an ionic bond)? You may assume that one protein attaches to one + charge on the beads (although it's possible that proteins attach to more than one + charge). B. After reaching 80% capacity, explain what you would do to release the protein attached to the…
- Consider the following protein mixture: Protein A B C D Molecular Weight (kDa) 50 150 200 350 Affinity to Metal ion === Zn²+ === 1. Using hydrophobic interaction chromatography, the protein that will be eluted last is [Select] 2. Using affinity chromatography, the protein that will be eluted last in a Zn²+-containing column is 3. The protein with the fastest migration towards the anode in SDS-PAGE is [Select] IpH value 7 3 9 5 [Select] [Select] 4. Using a buffer solution with a pH of 4, the protein that will bind to an anion exchanger is 5. The protein that will be eluted last in a gel filtration column is [Select] 6. Using isoelectric focusing, the protein that will have a protein band nearest to the cathode (negative electrode) is [Select] % Hydrophobicity 20 45 75 55A large chaperone protein complex GroEL is approximately 16 nm in diameter. When it is dissolved in water at 300 K, estimate the average time it will take for GroEL to diffuse a distance of 500 nm (0.5 micron). The viscosity of water is 10-3 Pa*s.A 20µL unknown protein was mixed with 80µL of water. Then, 10µL of this mixture was added with 10µL Bradford reagent and diluted with water to a total volume of 100µL. The absorbance at 595 nm shows 0.08 units. Solve for the protein concentration (in mg/mL) of the original unknown protein. How much protein (in mg) is in the 20uL sample? Express your answer in 3 significant figures.