Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 6, Problem 6.33P
To determine
The photon flux in
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Chapter 6 Solutions
Introduction To Health Physics
Ch. 6 - A 50-µC/kg (approximately 200 mR) pocket dosimeter...Ch. 6 - Prob. 6.2PCh. 6 - Prob. 6.3PCh. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - Prob. 6.6PCh. 6 - Prob. 6.7PCh. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10P
Ch. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.14PCh. 6 - Prob. 6.15PCh. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.20PCh. 6 - Calculate the average power density, in watts per...Ch. 6 - Prob. 6.22PCh. 6 - Prob. 6.23PCh. 6 - Prob. 6.24PCh. 6 - Prob. 6.26PCh. 6 - Prob. 6.27PCh. 6 - Prob. 6.28PCh. 6 - Prob. 6.29PCh. 6 - Prob. 6.33P
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- In real recording situations there are multiple devices that each have their own sampling rate. An audio file's sample rate is determined by the set up's lowest quality (smallest) sampling rate. Examine these recording set ups and determine the Nyquist frequency of the resulting digital file: Set up 1: 1. A microphone with a sampling rate of 48,000HZ 2. An audio processor with a sampling rate of 41,000HZ 3. What is this set up's Nyquist Frequency: Set up 2: 1. A speaker with a sampling rate of 46,050HZ 2. A microphone with a sampling rate of 12,000HZ 3. What is this set up's Nyquist Frequency: Set up 3: 1. A speaker with a sampling rate of 4,000HZ 2. A microphone with a sampling rate of 48,000HZ 3. An audio processor with a sampling rate of 41,000HZ 4. What is this set up's Nyquist Frequency:arrow_forwardQuestion: The radionuclide Tc-99m is a gamma photon emitter. The emitted gamma photonenergy is 141 keV. The scintillation crystal in a Gamma camera will convert the single gammaphoton to a burst of visible photons. Assuming the generated visible photons wavelength is 550nm, calculate how many visible 550-nm photons will have the same amount of energy as a single141-keV gamma photon?arrow_forwardAt around 150keV, If you know that the mass attenuation coefficient of lead is around 4 cm2 /g, and that its density is 11.34 g/cm3 : a) What is the half-value layer (HVL) of lead at this photon energy? b) How many sheets of HVL thickness you need to use in order to attenuate the X-ray beam at around 150keV to be lower than 10-3 of its incident intensityarrow_forward
- In a diagnostic x-ray procedure, 5.25×1010 photons are absorbed by tissue with a mass of 0.590 kg. The x-ray wavelength is 2.00×10−2 nm. A) What is the total energy absorbed by the tissue? Express your answer in millijoules. B) What is the equivalent dose in rem? Express your answer in rem.arrow_forwardA Perspex (Lucite) phantom is used to calibrate a 6 MV photon beam. A cylindrical air ion chamber has a wall thickness (polystyrene) of 0.20 g/cm2 and an inner diameter of 5 mm. The ion chamber is placed at a depth of 5 cm in the phantom. The NxAion = 1.05 × 1010 R/C (T = 22 oC, P = 760 torr) for Co-60 for this chamber. Charge collected is 2.50 × 10-8C at P = 750 torr and T = 20.0 oC. The ion collection efficiency is 0.985. (a) Calculate the Ngas (Gy/C) for the chamber. (b) Calculate the absorbed dose (Gy) in Perspex at this depth. (c) What would be the absorbed dose (Gy) in water at approximately the same depth in a water phantom?arrow_forwardThe point source Co-60 emits gamma with energies of 1.17 MeV and 1.33 MeV. Each of these energies emits the same number of photon particles. At a certain location, the flux read is 5.7 x 109 photons/cm2.s, what is the flux energy for 1.17 MeV for 24 hours of radiation exposure?arrow_forward
- IB. Wliv is a PET scan more accurate than a SPECT scan?arrow_forwardA 0.025 nm X-ray source deposits 30 million photons into 10 grams of tissue. What is the absorbed dose in the tissue (in Gy)? What is the dose equivalent (in Sv)?arrow_forwardTwo monoenergetic neutron beams of intensities I1=2x1010 neutrons/cm2.s and I1=1x1010 neutrons/cm2.s intersect at an angle of 30o. Calculate the neutron flux and current in the region where they intersect.arrow_forward
- A technique of 40 mAs , 200 kV, 200 cm SID produces 0.12 Gy exposure. If we change the technique to: 80mAs, 175 kV at 100 cm SID find the new exposure in rad?arrow_forwardA small 10-gram source of cobalt-60 is in a vacuum. (a) What is the activity of the cobalt-60source in Bq? (b) What is the actual gamma-ray flux in cm2-s-1 at a point of measurement500 cm from the source due to the cobalt-60 emitted gamma-rays? (c) If the backgroundgamma-ray flux in the vicinity of the 10-g source is 7.8×107cm-2-s-1, what is the totalgamma-ray flux at the point of measurement, including the background? (d) What thicknessof a lead shield in cm would have to be placed between the source and the point ofmeasurement to reduce the total of the background plus the uncollided gamma-ray flux fromthe cobalt-60 source to 1.00×108cm-2-s-1 at that point? (I've attempted part a of the problem and don't know how to continue)arrow_forwardGamma-ray detectors like the one described in the preceding problem often use calorimetry to determine gamma-ray energies. Suppose a beam of 100-MeV gamma rays strikes a target with a mass of 2.5 kg and specifi c heat 430 J/(kg # K). How many gamma rays are needed to raise the target’s temperature by 10 mK?arrow_forward
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