Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 4, Problem 4.3PFS
To determine
The lightest section of
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A PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown.
The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm,
respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the
steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN.
Neglect block shear.
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E.
• D
A
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Prob 01: An 18” depth beam is bolted to a 24” depth girder is connected similar to that in figure shown below. Thediameter of the rivet is 20mm and the angles are each 100mm x 100mm x 12mm thick. For each bolt, assume thatthe allowable bearing stress is 220 MPa. Determine the allowable load P in KN on the connection. *show all theload P in kN for bearing stressBeam web thickness = 5mmGirder web thickness =
A PL40 mm X 250 mm (smaller member) is connected to a gusset
plate (bigger member) as shown. The diameter of the holes are 25
mm. The pitch and gage of the holes are 50 mm and 75 mm,
respectively. The yield strength of the steel is 260 MPa while the
ultimate tensile strength of the steel is 400 MPa. Determine the
design (LRFD) tensile strength of the tension member in kN.
Neglect block shear.
H
G
P
P
D
B
F
C
A
E
Chapter 4 Solutions
Structural Steel Design (6th Edition)
Ch. 4 - Prob. 4.1PFSCh. 4 - Prob. 4.2PFSCh. 4 - Prob. 4.3PFSCh. 4 - Prob. 4.4PFSCh. 4 - Prob. 4.5PFSCh. 4 - Prob. 4.6PFSCh. 4 - Prob. 4.7PFSCh. 4 - Prob. 4.8PFSCh. 4 - Prob. 4.9PFSCh. 4 - Prob. 4.10PFS
Ch. 4 - Prob. 4.11PFSCh. 4 - Prob. 4.12PFSCh. 4 - Prob. 4.13PFSCh. 4 - Prob. 4.14PFSCh. 4 - Prob. 4.15PFSCh. 4 - Prob. 4.16PFSCh. 4 - Prob. 4.17PFSCh. 4 - Prob. 4.18PFSCh. 4 - Prob. 4.19PFSCh. 4 - Prob. 4.20PFSCh. 4 - Prob. 4.21PFSCh. 4 - Prob. 4.22PFSCh. 4 - Prob. 4.23PFSCh. 4 - Prob. 4.24PFSCh. 4 - Prob. 4.25PFSCh. 4 - Prob. 4.26PFS
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- Determine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117arrow_forward1. For the Pratt bridge truss and the loading shown below, determine the average normal stress in member BE, knowing that the cross-sectional area of that member is 60 in². NN K 12-12--12--12--| 50 lips 50 kips 50. ips Figure 1 G xfonearrow_forwardAW 12 x 65 column section shown in the figure is pinned at each end and has an additional support in the weak direction at a point 4.1 m from the top. Use X- 4.8 m K 1 for both directions. X+Y Properties of W 12 x 65 A 12323 mm2 - 134.11 mm ry 76.71 mm Fy- 248 MPa Determine the allowable compressive strength (kN).arrow_forward
- HOMEWORK-1 Зт IF For the truss shown in the figure; a) Calculate the bar forces for F=4000 kg. b) Design members 1-2 and 2-3 assuming that out of plane deflections are restrained and Aer>>10, i.e. global buckling is not the critical failure mode and therefore linear static analysis is sufficient. P.S. Use square rectangular hollow sections in Grade 355 steel. You will have to find the related section tables from the internet. Do not forget to refer to the related EN1993-1-1 tables and equations. Later, you will design the connections (the weld lengths, etc.) and the supports for this problem.arrow_forwardProblem 4: Use A992 steel and select a W shape. The service dead load is 142 kips, and the service live load is 356 kips. ↑ a 10' wwww Do wwwwww y-axis 16' x-axisarrow_forwardTwo bolts are used to lap points two steel plates. Tensile force on the plate is 45kN. Determine the required diameter of the bolts if the failure shear stress of the bolts is 350 MPa. Use a factor of safety for shear equal to 2.0arrow_forward
- Problem 2 Given is a truss structure: Where: • Working shear stress for the rivets is 70 MPa • Working bearing stress due to rivets is 140 Mpa • Thickness of the member is 5 mm • Thickness of the Gusset plate is 6 mm Rivet diameter is 15 mm Determine the no. of rivets to fasten the member BD 80 N 120 N 200 N 4 Pands 4m - 16 marrow_forwardGiven the truss shown, solve the following. Use A36 steel and assume there are two lines of three 19 mm bolts in each flange. Hole diameter is assumed to be three mm more than the bolt diameter. Neglect the weight of the section. a.What is the capacity of member CG? b. Design member CG using a W section. c. What is the tensile capacity of the section for CG based on gross area? The following W Section were considered for the design: W10x33 W14x38 W8x40 W16x36 W10x39 W8x13 189 KN 1.50 HL B 145 KN 1.50 E + 137 KN 121 KN -3.00 + 12.00 3.00 154 KN + W4x13 W6x9 W10x12 200 KN -1.50 1.50 1 030 T 1.20 +2.40 0.60 L i 0.30arrow_forwardInstructions:-Write down each step clearly in calculation suggestion what you are doing.( you need to tell why you selected particular value ofø (phi) and U). What and why you are calculating certain step Consider R= 433.5 PROBLEM A welded tension member is consisting of two channels placed 400mm back to back with flanges turned out. Select a channel for factored tensile of 4RKN using A36 steel and AISC specifications.The member is to be 15m long. PLASE USE THE EXAMPLE AS GUIDE OF ALL STEPS AND FORMULAS TO BE USEarrow_forward
- 2. A vertical member of a steel truss is subjected to a live load of 25 kN and a service dead load of 50 KN. The flat bar is welded to the guzzette plate with sufficient weld length such that the reduction factor "U" is equal to 1.0. Determine if a 10mm x 100mm plate is safe to carry the load. Given: Ag = 1000 sq mm width = 100mm thickness = 10 mm U = 1.0arrow_forwardThe lap joint in the figure is fastened by four 20 mm Ø A325X bolts. Calculate the maximum safe load P that can be applied if the plates are 25 mm thick A-36 steel Use ASD. 4 @ 40 mm P 2 @ 60 mm Parrow_forwardThree plates (14 mm and 16 mm in thickness) are welded to a W10 x 49 to form a built-up shape as shown. K.L= K.L= 7.6 m and F= 345 MPa, compute the design strength for LRFD. Mm x300mm WIOX49 14mm Piate Platearrow_forward
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