Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Textbook Question
Chapter 36, Problem 2SQ
Do secondary resistors on starters with three or more steps of acceleration have more or less current inrush than those with two steps of acceleration?
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General questions
4- In series d-c generator the field winding will be constructed from high number of
turns and high cross-sectional area of wire.
5-Series motor maintains a more constant speed under varying load
6-The armature voltage of d.c series generator is not affected by load current.
7- In series d-c generator the field winding will be constructed from high number of
turns and high cross-sectional area of wire.
8- If field resistance of a d.c. shunt generator is increased beyond its critical value, the
generator output voltage will exceed its rated voltage
9-The inter pole winding is connected in parallel to field winding.
10- in de machine the interpole winding connected across the armature winding.
Chapter 36 Solutions
Electric Motor Control
Ch. 36 - Are the secondary resistors connected in three...Ch. 36 - Do secondary resistors on starters with three or...Ch. 36 - Does reversing the secondary rotor leads mean that...Ch. 36 - If one of the secondary resistor contacts (S2)...Ch. 36 - In Figure 362, how many different interlocking...Ch. 36 - Referring to Figure 364, why is it not possible to...Ch. 36 - Prob. 7SQCh. 36 - If there is a locked rotor in the secondary...Ch. 36 - Why is it necessary to remove the jumpers in...Ch. 36 - Prob. 10SQ
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- Why are circulating currents detrimental to good motor operation?arrow_forwardSelect the best answer for each of the following. The purpose of overload protection on a motor is to protect the a. motor from sustained overcurrents. b. wire from high currents. c. motor from sustained overvoltage. d. motor from short circuits.arrow_forwardQ2- Indicate whether the following statements are true or false and correct the false statements 1- are placed at the magneti tral axis erator is not red by 10au o generator ffected by load current 4- A lap winding is most suitable for higher voltage rating machines 5- In dc generator, the critical resistance can be increased by increasing its speed 6-In LAP winding the front pitch equal to (yr ye- yb). 7- The speed of d.c series motor is decreased if the armature current is decreased 8- The compensating winding carrying the field current 9- By tapping field method, the speed of d.c series motor can be controlled below rated value 10- To solve the Commutation Problem in small machines, this can be achieved by increasing the brush widtharrow_forward
- Explain the other types of interlocks (aside from using push button contact) that are used in the forward and reversing circuit shown below that prevent the forward and reverse motor starter coils from being energized at the same time. L1 STOP FORWARD REVERSE NO E RINO RE BUZZER F R OL tillk FORWARD REVERSE 98 L2 STOP 95arrow_forwardQuestion 2 of 9 AC motor overloadding causes high current and high temperature, which causes the winding insulation to fail. O Rotor O Stator O Armature O Interpole Flag Reset Previous Next Go to Overviewarrow_forwardConsider a system with four pushbuttons and three lamps and three motors. PB 1 is used for main system ON. PB 4 is used Main OFF. Lamp 1 has to switch ON for the moment PB 2 is pressed. If the PB 2 is pressed for ten times lamp 2 has to ON. Motor 1 has to switch ON for the moment when PB 2 and PB 3 is pressed. If PB 3 is pressed for five times motor 2 has to ON.arrow_forward
- Complete the wiring diagrams as per Worksheets 5-A and 5-B then solve for "A" through "G" for the DC motor on Worksheets 5-A and 5-B when it is running at capacity and its specifications are as follows:Rated input = 125 volts, 16 ampsArmature Resistance = 0.3 ohms(Ω)Shunt Field Resistance = 50 ohms (Ω)Series Field Resistance = 0.6 ohm (Ω)Rheostat Resistance = 12.5 ohm (Ω)A) Shunt field current (I-shunt)a) 2.5 A b) 13.5A c) 16 A d) 18.5 AB) Armature current (I-arm)a) 2.5 A b) 13.5A c) 16 A d) 18.5 AC) Voltage drop of shunt field (I-shunt)a) 4.05 V b) 120.95 V c) 125 V d) 129.5 VD) Voltage drop of armature (IR-arm)arrow_forwardComplete the wiring diagrams as per Worksheets 5-A and 5-B then solve for "A" through "G" for the DC motor on Worksheets 5-A and 5-B when it is running at capacity and its specifications are as follows:Rated input = 125 volts, 16 ampsArmature Resistance = 0.3 ohms(Ω)Shunt Field Resistance = 50 ohms (Ω)Series Field Resistance = 0.6 ohm (Ω)Rheostat Resistance = 12.5 ohm (Ω)A) Voltage drop of armature (IR-arm)a) 4.05 V b) 120.95 V c) 125 V d) 129.5 VB) Voltage generated by motor (E-cemf)a) 4.05 V b) 120.95 V c) 125 V d) 129.5 VC) power consumed by shynt field(p-shunt)a) 54.68 W, b) 312.5 W, c) 1632.83 W, d) 2000 WD) power consumend by armature resistance( P-arm)a) 54.68 W , b) 312.5 W, c) 1632.83 W , d) 3000 Warrow_forwardHow can you reduce the amount of voltage applied to the motor during inching?arrow_forward
- A 400V D.C. shunt motor takes 5 A at no-load. R = 0.5 ohms, R,= 200 ohms. What is the ratio %3| %D a f of speed from full load to no-load, when the D.C. shunt motor takes 50 A on full load? (b) 0.8 (d) 0.4 (а) 0.94 (c) 0.6arrow_forwardIncorrect Question 21 When an electrical load is connected to a DC generator, current flows None of the Answers O through the armature only O through the commutator segments only O through the armature and brushes only through the brushes onlyarrow_forwardComplete the wiring diagrams as per Worksheets 7-A and 7-B then solve for "A" through "K" for the DC motor on Worksheets 7-A and 7-B when it is running at capacity and its specifications are as follows:Rated input = 125 volts, 16 ampsArmature Resistance = 0.3 ohms(Ω)Shunt Field Resistance = 50 ohms (Ω)Series Field Resistance 0.6 ohms (Ω)Rheostat Resistance = 12.5 ohms (Ω)A)power consumed by series field(P-series)a)56.58W b)153.6W c)265.42W d)1523.WB)power consumed by shunt field(P-shunt)a)56.58W b)153.6W c)265.42W d)1523.56WC)power consumed by armature resistance(P-arm)a)56.58W b)153.6W c)265.42W d)1523.56WD)percent efficiency of the machine( % eff) if rotational loses are 850 Wa)30% b)64% c)86% d)99%arrow_forward
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