Problem Solving with C++ (10th Edition)
10th Edition
ISBN: 9780134448282
Author: Walter Savitch, Kenrick Mock
Publisher: PEARSON
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Chapter 18.2, Problem 13STE
Program Plan Intro
Member functions in stack template adapter class:
The member functions in stack templates are given below:
- “s.size()”:
- This function is used to returns the number of elements in the stack.
- “s” is object of stack template adapter class.
- “s.empty()”:
- This function is used to returns “true” if the stack is empty.
- Otherwise, this function returns “false”.
- “s.top()”:
- This function is used to returns top value of the given stack.
- “s.push(Value)”:
- This function is used to insert a “Value” to the top of stack.
- “s.pop()”:
- This function is used to removes the top value of the stack.
- In stack, the “pop” function is a void function.
- So, it does not return the removed value.
- “st1 == st2”:
- This function is used to check whether the
two stacks are equal or not. - If “st1.size == st2.size”, then returns “true”. That is if the number of elements in stack “st1” is equal to corresponding elements in stack “st2”.
- Otherwise, returns “false”.
- This function is used to check whether the
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C++ PROGRAMMINGTopic: HashTable - PolyHash Quadratic
Explain the c++ code below.: SEE ATTACHED PHOTO FOR THE PROBLEM INSTRUCTIONS It doesn't have to be long, as long as you explain what the important parts of the code do. (The code is already implemented and correct, only the explanation needed). You can also explain line by line for an upvote, thanks.
EXPLAIN THE CODE BELOW:
#include <cstdlib>
#include <math.h>
#include <cstring>
#include <iostream>
using namespace std;
class HashTable {
string* table;
int N;
int count;
// TODO: Polynomial Hash Code using a=7
int hash_code(string key) {
int code;
int hash = 0;
for (int i = 0; i < key.size(); i++) {
char ch = key[i];
code += ((ch - 96) * pow(7, key.size() - (i + 1)));
}
return code;
}
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// where a = 11, b = 461, p = 919
int compress(int code) {
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Write a program to evaluate an expression entered in “postfix” form using the stack concept.Assume: The operators in the expression will not be other than '+' , '-' , '*' ,or '/'.
The class Postfix has the following method.
Method Name
Method Description
public double evaluate(string exp)
This method accepts a string as an expression from the Main method, evaluates the string in the “postfix” form.
It returns the double value obtained after evaluated in “postfix” form.
[Note: The method should be invoked through the main function.]Sample Input and Output:[ All text in bold corresponds to input and the rest corresponds to output ]Enter postfix expression to be evaluated:13+Result is : 4
Explanation:
First number is 1Second number is 3Operator is +So in postfix form, it is evaluated as 1+3 = 4
How does the --> work in dereferencing a pointer?
Chapter 18 Solutions
Problem Solving with C++ (10th Edition)
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