Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 17, Problem 4P
What is the maximum angular diameter of Phobos as seen from Earth? (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.) (Note: Useful data can be found in the chapter text and in Appendix Table A-10.)
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Venus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU).
What would its apparent magnitude be?
Venus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination
phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU).
times fainter
What would its apparent magnitude be?
Need Help?
Read It
What is the angular diameter of Saturn (in degrees) as seen from the surface of Hyperion? (Note: Necessary data can be found https://www.webassign.net/seedsfoundations14/22-celestial-profile-saturn.pdf and in this table https://www.webassign.net/seedsfoundations14/a-table-11.pdf)( Hint: Use the small-angle formula)
_________ degrees
Chapter 17 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 17 - Prob. 1RQCh. 17 - Why does Mercury have lobate scarps but Earth,...Ch. 17 - What evidence indicates that plate tectonics does...Ch. 17 - Prob. 4RQCh. 17 - Why are the atmospheres of Venus and Mars mostly...Ch. 17 - Prob. 6RQCh. 17 - Prob. 7RQCh. 17 - Why do astronomers conclude that the crust on Mars...Ch. 17 - Prob. 9RQCh. 17 - Prob. 10RQ
Ch. 17 - Prob. 11RQCh. 17 - Prob. 1DQCh. 17 - Imagine that you visit a planet orbiting another...Ch. 17 - Imagine that a spacecraft has landed on Mercury...Ch. 17 - Prob. 2PCh. 17 - The smallest detail visible through Earth-based...Ch. 17 - What is the maximum angular diameter of Phobos as...Ch. 17 - Phobos obits Mars at a distance of 9376 km from...Ch. 17 - Volcano Sif Mons on Venus is shown in the radar...Ch. 17 - Prob. 2LTL
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- What is the maximum angular diameter of the dwarf planet Ceres when it is closest to Earth? Could Earth-based telescopes detect surface features? Could the Hubble Space Telescope? (Hint: Use the small-angle formula, Eq. 3-1.) (Notes: Ceress average distance from the Sun is 2.8 AU and its diameter is 950 km. The best angular resolution of Earth-based telescopes at visual wavelengths is about 1 arc second and of Hubble about 0.1 arc second.)arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1AU. How many times fainter would Venus look from a distance of 7pc? Assume Venus has the same illumination phase from your new vantage point. (Hint: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 10^5 AU _______ times fainter what would it's apparently magnitude be? _______arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 105 AU). times fainter What would its apparent magnitude be?arrow_forward
- What is the angular diameter of Saturn (in degrees) as seen from the surface of Dione? Note: Necessary data can be found in this Celestial Profile and in this table. Hint: Use the small-angle formula, angular diameter (in arc seconds) 2.06 ✕ 105 = linear diameter distancearrow_forwardConsider an asteroid that orbits in a relatively circular orbit with a semimajor axis a = 2 au from the Sun. A typical asteroid has an albedo, or reflectivity, A ~ 0.3. At our closest approach to the asteroid, we make a measurement of the flux coming from the asteroid to be F = 3 × 10-15 w m-2. What is the radius of the asteroid in km? Include a labelled diagram along with your calculations.arrow_forwardThe asteroid Hygiea has a mass of 8.67 x 1019 kg and an average radius of about 216 km (2.16 x 102 km). What is its escape velocity (in m/s)? (Hints: Use the formula for escape velocity, 2GM ; remember to convert units to m, kg, and s.) r e m/s Could you jump off the asteroid? Yes No Need Help? Read It Submit Answerarrow_forward
- Tutorial You observe a comet 0.32 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? How long is the tail in kilometers? How many times could the U.S. fit along the length of the tail? (The width of the U.S. is 4,313 km.) Part 1 of 3 You observe a comet 0.32 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? We use the small angle formula to calculate the length of the tail in AU. arc seconds d Ꮎ 2.06 x 105 D Solving for the linear distance gives: dAU = DAU dAU = = AU arc seconds 2.06 x 105arrow_forwardIn 2015, researchers concluded that Enceladus's subsurface ocean is probably global, instead of just being restricted to the south polar region. What had the Cassini spacecraft found, that led them to their conclusion? a Enceladus wobbles slightly as it orbits Saturn, more so than it could if its ice shell were mostly frozen to the rocky interior. b Enceladus is absorbing so much water (which is ejected by Saturn from its atmosphere) that there must be a global ocean under its icy surface. c The number of large, lava-spewing volcanoes on Enceladus's surface is so high that they can only be the result of liquid water under the whole surface. d The magnetic field of Enceladus is so strong that it can only be explained by a global ocean of salty water under the surface.arrow_forwardAt what average distances (in AU) from the Sun would you expect to find Kirkwood gaps where the orbital period of asteroids are respectively four-ninths, and two-fifths, of the orbital period of Jupiter? (Hint: use Kepler's third law.) inner gap at AU outer gap at AU Compare your results with the figure. 7:2 3:1 8,3 5;2 7:3 9:4 2;1 9:5 7:4 53 8:5 3:2 Resonances Gap Gap Gap Gap GapGap Gap Distance from sun (AU) O The results agree with the figure. O The results do not agree with the figure.arrow_forward
- The value we have just calculated is the combined masses of Jupiter and Callisto! Their mass is in units of the Sun's Mass (MS) - we can convert this to units which are more familiar to us like kilograms by multiplying this answer by the scale factor (1.99x1030 kg/1 MS): (MJupiter + MCallisto) = ( MS) (1.99x1030 kg/1 Solar Mass) = _______x_10___ kg (I have already written the x 10 so you are reminded to write the exponenet of 10 in the scientific notation expression of your answer). Since you know from looking at pictures of Jupiter with its Galilean Satellites (look in your book at a picture if you have not already), that Callisto is much smaller than Jupiter - in fact it is less than 0.001 of Jupiter's size or mass, so the number we have just calculated for (MJupiter + MCallisto) is almost the same as MJupiter . How much more massive is Jupiter than the Earth? (The mass of Earth is about 5.98 x 1024 kg)arrow_forwardIf you stood on Earth during its formation, during which it captured about 1.6 ✕ 1011 particles per second, and watched a region covering 170 m2, how many impacts would you expect to see in an hour? (Notes: The surface area of a sphere is 4?r2. Hint: Assume that Earth had its current radius of 6,378 km.)arrow_forwardAt what average distances (in AU) from the Sun would you expect to find Kirkwood gaps where the orbital period of asteroids are respectively four-ninths, and three-sevenths, of the orbital period of Jupiter? (Hint: use Kepler's third law.) Compare your results with the figure.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY