Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 17, Problem 2P
To determine
The total time required by a radio signal to travel from the Earth to the Venus and back in situations where Venus is at its nearest approach to Earth and when it is at its farthest distance from the Earth.
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Chapter 17 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 17 - Prob. 1RQCh. 17 - Why does Mercury have lobate scarps but Earth,...Ch. 17 - What evidence indicates that plate tectonics does...Ch. 17 - Prob. 4RQCh. 17 - Why are the atmospheres of Venus and Mars mostly...Ch. 17 - Prob. 6RQCh. 17 - Prob. 7RQCh. 17 - Why do astronomers conclude that the crust on Mars...Ch. 17 - Prob. 9RQCh. 17 - Prob. 10RQ
Ch. 17 - Prob. 11RQCh. 17 - Prob. 1DQCh. 17 - Imagine that you visit a planet orbiting another...Ch. 17 - Imagine that a spacecraft has landed on Mercury...Ch. 17 - Prob. 2PCh. 17 - The smallest detail visible through Earth-based...Ch. 17 - What is the maximum angular diameter of Phobos as...Ch. 17 - Phobos obits Mars at a distance of 9376 km from...Ch. 17 - Volcano Sif Mons on Venus is shown in the radar...Ch. 17 - Prob. 2LTL
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- What is the escape velocity is km/s from Venus' exosphere, which begins about 202 km above the surface ? Assume the gravitational constant is G= 6.67 x10-11m3 kg-1s-2, and that's Venus has a mass of 5.2e+24 kg and a radius of 6500.0 kmarrow_forwardThe fraction of the energy flux received which is reflected into space is the albedo of Venus, av, which is about 0.76. The fraction of the energy flux which is absorbed is then (1-av) = 1. - 0.76 = 0.24. So the amount of energy actually absorbed by Venus in each second is Lv = (1-av)Ev. Lv = (1-av)Ev = ___________________ ergs/s And next calculate the effective temperature of Venus: Tv4 = (Lv/(4pdv2))/s = Lv/(4spdv2) = __________________ K4 and taking the square root of Tv4 twice in succession we get the effective Temperature Tv: Tv = [Lv/(4spdv2)]0.25 = _________________ K Calculate Venus' emittance assuming that the Venus' actual temperature, Tvr, is 472o C = 745 K: ev = Lv/(4pdv2s Tvr4) = __________________ .arrow_forwardOn the night side of Venus, we find that the brightest wavelength, that is the wavelength this region of the planet is emitting the most energy, is about 3.9 micrometres (3.9x10-6 meters). Approximately how warm is the planet in this region?arrow_forward
- At an average opposition, the Earth and Mars are separated by 0.52 AU. Suppose an astronomer observes Mars at opposition and that seeing blurs the images to a resolution of 1.0 seconds of arc. What is the smallest surface feature the astronomer would be able to resolve on Mars? How does this size compare with the diameter of Mars?arrow_forwardCalculate how long radio communications from the spacecraft will take when it encounters Mars. The furthest distance from Earth to Mars is 2.66 AU. Remember that 1 AU = 1.5 x 1011 m and that light travels at 3 x 108 m/s. So how long will the radio messages take to travel this greatest distance of 2.66 AU? If two way communication between the Earth and the spacecraft involve a 1 s time lapse before an acknowledging signal is sent by the spacecraft, how long a time is there between sending a command to the spacecraft and receiving a reply?arrow_forwardThe runaway greenhouse effect and its inverse, the runaway refrigerator effect, have led to harsh, uninhabitable conditions on Venus and Mars. Does the greenhouse effect always cause climate changes leading to loss of water and life? Give a reason for your answer.arrow_forward
- Describe two anomalous features of the rotation of Venus and what might account for them.arrow_forwardWhy is there so much more carbon dioxide in the atmosphere of Venus than in that of Earth? Why so much more carbon dioxide than on Mars?arrow_forwardHow long would radio signals take to travel from Earth to Venus and back if Venus were at its nearest point to Earth? At its farthest point from Earth? (Notes: The speed of light is 3.00 108 m/s. Necessary data to derive the distances between the objects in those two situations are given in the Celestial Profiles for Earth in Chapter 19 and Venus in this chapter.)arrow_forward
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