Fluid Mechanics: Fundamentals and Applications
Fluid Mechanics: Fundamentals and Applications
4th Edition
ISBN: 9781259696534
Author: Yunus A. Cengel Dr., John M. Cimbala
Publisher: McGraw-Hill Education
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Chapter 15, Problem 4CP
To determine

A sketch of unstructured grid using three-sided cell.

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The center of mass for a human body can be determined by a segmental method. Using cadavers, it is possible to determine the mass of individual body segments (as a proportion of total body mass) and the center of mass for each segment (often expressed as a distance from one end of the segment). Finding the overall body center of mass can be a complex calculation, involving more than 10 body segments. Below, we will look at a simplified model that uses just six segments: head, trunk, two arms, and two legs. Search y X As a percentage of total body mass, the head is 10%, the two arms are 10%, the trunk is 56%, and the two legs are 24%. The center of mass for each segment is given as an (x,y) coordinate, both units in cm: head = (0, 165), arms = (0, 115), trunk = (0, 95), and legs = (0, 35). Assume the body mass for the individual is 88 kg and their total height is 180 cm. Determine they and y coord 99+ H of mass
I am trying to find a Direction Cosine Matrix (DCM) for the Euler angle body 1-2-3 sequence. I tried making my own function and using the MATLAB function, but the result is a matrix that is transpose of each other. I mean that transpose(EA123toDCM) = E123toDCM. Why is that? Also, for the E123toDCM line, I am using the sequence 'ZYX'. Is that correct or should it be 'XYZ'? I know that that for a DCM of sequence 1-2-3 = R3(theta1)*R2(theta2)*R1(theta3). Is ZYX sequence the same as a 1-2-3 sequence?   EA = [pi/3; -pi/4; -pi/6];EA123toDCM = EA123DCM(EA) E123toDCM = angle2dcm(EA(1,1), EA(2,1), EA(3,1), 'ZYX')   function [R] = EA123DCM(EA)     theta1 = EA(1,1);    theta2 = EA(2,1);    theta3 = EA(3,1);            R1 = @(a)[1    0      0    ;              0  cos(a) -sin(a);              0  sin(a) cos(a)];              R2 = @(a)[cos(a)  0 sin(a) ;                0     1   0    ;              -sin(a) 0 cos(a)];              R3 = @(a)[ cos(a) -sin(a) 0;               sin(a) cos(a)  0;…
For the two-dimensional computational domain of Fig, with the given node distribution, sketch a simple structured grid using four-sided cells and sketch a simple unstructured polyhedral grid using at least one of each: 3-sided, 4-sided, and 5-sided cells. Try to avoid large skewness. Compare the cell count for each case and discuss your results.
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