Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
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Chapter 10.8, Problem 37E

a.

To determine

Write the system of equations for dimensions of pen.

a.

Expert Solution
Check Mark

Answer to Problem 37E

  2(x+y)=150xy=800

Explanation of Solution

Given information:

Carrie has 150meters of fencing material to make a rectangular pen with area 8002meters . x width and y be the length of pen.

Calculation:

Length 150meters of fencing material, pen with area 8002meters .

Consider, the system of equation from length and area is,

  width=xlength=y

  2(x+y)=150....(1)xy=800.....(2)

Hence the system of equations is,

  2(x+y)=150xy=800

b.

To determine

Find the number of solutions for system of equations.

b.

Expert Solution
Check Mark

Answer to Problem 37E

Two Solutions.

Explanation of Solution

Given information Carrie has 150meters of fencing material to make a rectangular pen with area 8002meters . x width and y be the length of pen.

Calculation:

The system of equations is,

  2(x+y)=150xy=800

Two solutions are possible for this type of system of equations.

c.

To determine

Graph the estimated dimensions of pen.

c.

Expert Solution
Check Mark

Answer to Problem 37E

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.8, Problem 37E , additional homework tip  1

Explanation of Solution

Given information:

Carrie has 150meters of fencing material to make a rectangular pen with area 8002meters . x be width and y be the length of pen.

Calculation:

Graph the dimensions of pen,

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 10.8, Problem 37E , additional homework tip  2

d.

To determine

Solve the system of equations for dimensions of pen.

d.

Expert Solution
Check Mark

Answer to Problem 37E

  (62.12,12.88)and(12.88,62.11)

Explanation of Solution

Given information:

Carrie has 150meters of fencing material to make a rectangular pen with area 8002meters . x be width and y be the length of pen.

Calculation:

Consider,

  xy=800y=800x

Put y=800x in equation 2(x+y)=150 we get,

  x+y=75x+800x=75x275x+800=0nowusequadraticformula,x=b±b24ac2ax=(75)±(75)24×8002x=75±762532002x=75±24252x=75±49.242x=62.12,x=12.88y=80062.12=62.11,y=80012.88=12.88

Hence, width and length dimensions of pen are (62.12,12.88)and(12.88,62.11) .

Chapter 10 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 10.1 - Prob. 11CFUCh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.1 - Prob. 33ECh. 10.1 - Prob. 34ECh. 10.1 - Prob. 35ECh. 10.1 - Prob. 36ECh. 10.1 - Prob. 37ECh. 10.1 - Prob. 38ECh. 10.1 - Prob. 39ECh. 10.1 - Prob. 40ECh. 10.1 - Prob. 41ECh. 10.1 - Prob. 42ECh. 10.1 - Prob. 43ECh. 10.1 - Prob. 44ECh. 10.2 - Prob. 1CFUCh. 10.2 - Prob. 2CFUCh. 10.2 - Prob. 3CFUCh. 10.2 - Prob. 4CFUCh. 10.2 - Prob. 5CFUCh. 10.2 - Prob. 6CFUCh. 10.2 - Prob. 7CFUCh. 10.2 - Prob. 8CFUCh. 10.2 - Prob. 9CFUCh. 10.2 - Prob. 10CFUCh. 10.2 - Prob. 11CFUCh. 10.2 - Prob. 12CFUCh. 10.2 - Prob. 13CFUCh. 10.2 - Prob. 14CFUCh. 10.2 - Prob. 15ECh. 10.2 - 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