Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 10, Problem 10QP
- b. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individual’s cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individual’s cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column.
Denote the point in the pathway in which each individual is blocked.
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Students have asked these similar questions
A. Lineweaver-Burk plot of the enzyme with increasing amounts of substrate in the absence
or the presence of the inhibitor is shown below.
Graph A : x-intercept
Graph B : x-intercept = - 0.012, y-intercept = 0.8
Graph C : x-intercept = - 0.027, y-intercept = 0.8
Graph D : x-intercept = - 0.039, y-intercept = 0.8
- 0.007, y-intercept = 0.8
Graph A
4
Graph B
Graph C
Graph D
1
-0,04
-0,02
0,00
0,02
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1/[Substrate] (uM)
(i) Which graph indicates an enzymatic reaction without inhibitor?
(ii) Which type of inhibitor is it? Briefly explain.
(iii) Which graph indicates the highest concentration of inhibitor?
(iv) Calculate the Vmax and Km of the graph showing an enzymatic reaction with the lowest
concentration of inhibitor. Show the steps of calculation and unit in your answers.
Keep 2 decimal places in your answers.
1/Rate (umol/min)
a. An oligopeptide ALVGALGATPTPQMWSHSWRGVSIKS was digested with trypsin.Which method would be most appropriate for separating the products: ion exchange or gel filtration chromatography? Explain.b. Suppose that the peptide was digested with cyanogen bromide. What would be the optimal separation technique? Explain
This is an SDS-PAGE gel of the protein insulin. The first lane is the molecular weight standard marker. The second lane NR is the native, non-reduced protein (MW 5.7kDa). The third lane is the protein treated with beta-mercaptoethanol. Please explain what is shown in the NR lane versus the R lane.
Chapter 10 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 10.4 - Prob. 1GRCh. 10.4 - Prob. 2GRCh. 10.7 - Prob. 1EGCh. 10.7 - Prob. 2EGCh. 10 - A couple was referred for genetic counseling...Ch. 10 - A couple was referred for genetic counseling...Ch. 10 - A couple was referred for genetic counseling...Ch. 10 - Many individuals with metabolic diseases are...Ch. 10 - Prob. 2QPCh. 10 - Enzymes have all the following characteristics...
Ch. 10 - Questions 4 through 6 refer to the following...Ch. 10 - Questions 4 through 6 refer to the following...Ch. 10 - Prob. 6QPCh. 10 - Prob. 7QPCh. 10 - Prob. 8QPCh. 10 - a. Compounds A, B, C, and D are known to be...Ch. 10 - b. Compounds A, B, C, and D are known to be...Ch. 10 - a. If an individual who is homozygous for the...Ch. 10 - Prob. 12QPCh. 10 - Suppose that in the formation of phenylalanine...Ch. 10 - If phenylalanine was not an essential amino acid,...Ch. 10 - Phenylketonuria and alkaptonuria are both...Ch. 10 - The normal enzyme required for converting sugars...Ch. 10 - Knowing that individuals who are homozygous for...Ch. 10 - Prob. 18QPCh. 10 - A person was found to have very low levels of...Ch. 10 - If an extra nucleotide is inserted in the first...Ch. 10 - Transcriptional regulators are proteins that bind...Ch. 10 - Prob. 22QPCh. 10 - Prob. 23QP
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- a. Compounds A, B, C, and D are known to be intermediates in the pathway for production of protein E. To determine where the block in protein-E production occurred in each individual, the various intermediates were given to each individuals cel Is in culture. After a few weeks of growth with the intermediate, the cells were assayed for the production of protein E. The results for each individuals cells are given in the following table. A plus sign means that protein E was produced after the cells were given the intermediate listed at the top of the column. A minus sign means that the cells still could not produce protein E even after being exposed to the intermediate at the top of the column. Draw the pathway leading to the production of protein E.arrow_forwardtopic: Bradford AssayThere are numerous methods of protein determination in use, but this module focuses on the Bradford assay.The Bradford assay is a dye-binding method that employs Coomassie Brilliant Blue G-250, whose structureis shown in Figure 2.3.4.1. Coomassie Brilliant Blue G-250 is a dye that interacts with proteins throughhydrophobic and electrostatic interactions. What are the identities and functions of the components of the Bradford reagent in protein contentdetermination?arrow_forwarda. Why proteins are extracted to a buffered solution? Briefly describe the components of ageneralized protein extraction buffer?.b. Describe the basis of affinity chromatography in protein purification.c. What is the most appropriate method of protein elution in affinity chromatography?d. List three examples of commonly employed combinations of ligand and protein in affinitychromatography.arrow_forward
- ALANINE AMINOTRANSFIRASE AND ASPARTATE AMINOTRANSFERASE (KARMEN МЕТHOD) (C. chemistry) 1. state the reason why substrate must be incubated prior to the addition of serum 2. what part of the steps need extra to avoid positive results? 3. describe the principle of AST/ALT kinetic method.arrow_forwardwhat is lactose intolerance ? describe the molecular life cycle for this disease. also describe how it occurs in a molecular level detailed mechanism. what causes this disease and how it develops ? provide detailed biochemical phenomena and life cycle for Lactose Intolerance condition.arrow_forward(b) Both laboratories used 10 micrograms of protein each in their kinetic assays. Protein concentrations weredetermined by the Bradford protein assay. Assay conditions employed in the two labs (pH, temperature,etc.) were also identical. What would be the most plausible cause for the discrepancy in the Vmax valuesfor the compound I? Explain.Recall that the Bradford assay measures total protein amounts in sample solution based on complexformation between a dye and proteins. Also, the assay solution used in both labs does not contain anyinhibitors.arrow_forward
- Suppose that you are tasked to determine the protein concentration of an unknown protein solution via Bradford assay. You prepared six solutions of bovine serum albumin (BSA) with different concentrations. The initial concentration of the BSA stock solution is 7.50 mg/mL. Approximately 200 µL of Bradford Reagent was added to each of these solutions and the absorbance at 595 nm was taken after 5 minutes. See the table below for data on the standard solutions. Standard # A595 BSA conc (mg/mL) 0.000 0.158 2 1.125 0.291 2.250 0.372 4 3.375 0.503 5 4.500 6 5.625 0.675 Determine the protein concentration, in mg/mL, of the unknown solution if its absorbance at 595 nm was 0.248. Note: Final answer format must be x.xx (two decimal places). Round off only in the final answer. Do not round off in the middle of calculation.arrow_forwarda protein collected through affinity chromatography displays no activity even though it is found to have a high concentration using the bradford protein essay. what best explains these findings?arrow_forward*The enzyme glucose oxidase isolated from the mold Penicillium notatum catalyzes the oxidation of 3-D-glucose to D-glucono-6- lactose. This enzyme is highly specific for the ß anomer of In spite of this glucose and does not affect the a anomer. specificity, the reaction catalyzed by glucose oxidase is commonly used in a clinical assay for total blood glucose that is, for solutions consisting of a mixture of 3- and a-D- glucose. What are the circumstances required to make this possible? Aside from allowing the detection of smaller quan- tities of glucose, what advantage does glucose oxidase offer over non-enzymatic oxidizing agents like Tollens reagent? *Is B-D-glucosamine a reducing sugar?arrow_forward
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