The reaction of bromomethane with azide ion (N3-) in methanol is a typical SN2 reaction. What happens to the rate of the reaction if [N3-] is doubled?
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The reaction of bromomethane with azide ion (N3-) in methanol is a typical SN2 reaction. What happens to the
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- The reaction of tert-butyl bromide with azide ion (N3-) in methanol is a typical SN1 reaction. What happens to the rate of the reaction if [N3-] is doubled?In an SN2 reaction between 2-chlorobutane and iodide ion, what happens to the rate of the reaction if: (a) the concentration of 2-chlorobutane is doubled? (b) the concentration of iodide is doubled?9. (a) Under certain conditions, the reaction of 0.5 M 1-bromobutane with 1.0 M sodium methoxide forms 1-methoxybutane at a rate of 0.05 mol/L per second. What would be the rate if 0.1 M 1-bromobutane and 2.0 M NaOCH3 were used? (b) Consider the reaction of 1-bromobutane with a large excess of ammonia (NH3). Draw the reactants, the transition state, and the products. Note that the initial product is the salt of an amine (RNH* Br) which is deprotonated by the excess ammonia to give the amine. (c) Show another SN2 reaction using a different combination of an alkoxide and an alkyl bromide that also produces 1-methoxybutane.
- Peroxides are often added to free-radical reactions as initiators because the oxygen–oxygen bond cleaves homolytically rather easily. For example, the bond-dissociation enthalpy of the O¬O bond in hydrogen peroxide (H¬O¬O¬H) is only 213 kJ>mol (51 kcal>mol). Give a mechanism for the hydrogen peroxide-initiated reaction of cyclopentane with chlorine. The BDE for HO¬Cl is 210 kJ>mol (50 kcal>mol).Consider the attached SN2 reaction. Question: What happens to the reaction rate in each of the following instances? [1] The leaving group is changed from Br− to I−; [2] The solvent is changed from acetone to CH3CH2OH; [3] The alkyl halide is changed from CH3(CH2)4Br to CH3CH2CH2CH(Br)CH3; [4] The concentration of −CN is increased by a factor of five; and [5] The concentrations of both the alkyl halide and −CN are increased by a factor of five8) Write the mechanism of the following reaction? 1. NABH4 2. H20 OH
- CH3 CH3 Br- Br2 CH2CI2 CH3 CH3 H3C H3C Br Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2C12. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 Br- .CH3 .CH3 H3C H3C :Br :Br:(a) Under certain conditions, the reaction of 0.5 M 1-bromobutane with 1.0 M sodium methoxide forms 1-methoxybutane at arate of 0.05 mol>L per second. What would be the rate if 0.1 M 1-bromobutane and 2.0 M NaOCH3 were used?CF2Cl2 can be prepared from the nucleophilic substitution of another alkyl halide CCl4 in the presence of excess HF. CCl4 + 2HF -----> CF₂Cl2 + 2HCI. rate = k[CCl4] How long will it take for this reaction to reach 90% completion if the the rate constant for the reaction is 1.5 x 10- 4 5-1? Give your answer in hours to 1 d.p. Time required: hours
- Organic Chemistry Please provide explanation for how the steps of A through C result in the formation of 7-MethoxyphthalideWhen the alkyl bromides (listed here) were subjected to hydrolysis in a mixture of ethanol and water (80% EtOH/20% H2O) at 55 °C, the rates of the reaction showed the following order: (CH3)3CBR > CH3Br > CH3CH2Br > (CH3)2CHBR Provide an explanation for this order of reactivity.If the following molecules undergo free radical substitution, what is the order in which the hydrogen is easily replaced by bromine?