Reactions 1: Y=0.2x + 0.8 Reactions 3: Y=0.2x + 0.5 1/Vmax = 0.8 1/Vmax = 0.5 Vmax= 1/0.8 mM/min Vmax= 1/0.5 mM/min Vmax = 1.25 mM/min Vmax = 2 mM/min Km = 0.2 x 1.25 Km = 0.25 Km = 0.2 x 2 Km = 0.4

Principles Of Pharmacology Med Assist
6th Edition
ISBN:9781337512442
Author:RICE
Publisher:RICE
Chapter3: Ratio And Proportion
Section: Chapter Questions
Problem 7PP
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Match with the given reaction

A. The reaction with a non-competitive inhibitor
B. The reaction without inhibitor
C. The reaction with competitive inhibitor
D. The reaction with the fastest reaction

Reactions 1: Y=0.2x + 0.8
Reactions 3: Y=0.2x + 0.5
1/Vmax = 0.8
1/Vmax = 0.5
Vmax= 1/0.8 mM/min
Vmax= 1/0.5 mM/min
Vmax = 1.25 mM/min
Vmax = 2 mM/min
Km = 0.2 x 1.25 Km = 0.25
Km = 0.2 x 2 Km = 0.4
Reactions 2: Y=0.4x + 0.5
Reactions 4: Y=0.16x + 0.4
1/Vmax = 0.5
1/Vmax = 0.4
Vmax= 1/0.5 mM/min
Vmax= 1/0.4 mM/min
Vmax = 2 mM/min
Vmax = 2.5 mM/min
Km = 0.4 x 2 Km = 0.8
Km = 0.16 x 2.25 Km = 0.4
%D
%3D
%3D
Transcribed Image Text:Reactions 1: Y=0.2x + 0.8 Reactions 3: Y=0.2x + 0.5 1/Vmax = 0.8 1/Vmax = 0.5 Vmax= 1/0.8 mM/min Vmax= 1/0.5 mM/min Vmax = 1.25 mM/min Vmax = 2 mM/min Km = 0.2 x 1.25 Km = 0.25 Km = 0.2 x 2 Km = 0.4 Reactions 2: Y=0.4x + 0.5 Reactions 4: Y=0.16x + 0.4 1/Vmax = 0.5 1/Vmax = 0.4 Vmax= 1/0.5 mM/min Vmax= 1/0.4 mM/min Vmax = 2 mM/min Vmax = 2.5 mM/min Km = 0.4 x 2 Km = 0.8 Km = 0.16 x 2.25 Km = 0.4 %D %3D %3D
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