Q: For a basic computer that is currently running in its timing TO of execution for an instruction that is located in memory location 366. The content of AC is (212) and the content of memory locations are as follow: [memory location: content]: [365:9473], [366:7010], [367:5431], [368:4620], [431:1A23], [620:C80D]. Answer the following questions that examine the contents of PC, AR, AC, DR and IR after the end of execution for the next instruction. (.(Note: all numbers are in Hexadecimal

Microsoft Visual C#
7th Edition
ISBN:9781337102100
Author:Joyce, Farrell.
Publisher:Joyce, Farrell.
Chapter8: Advanced Method Concepts
Section: Chapter Questions
Problem 7RQ
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Q: For a basic computer that is currently running in its
timing TO of execution for an instruction that is located in
memory location 366. The content of AC is (212) and the
content of memory locations are as follow: [memory
location: content]: [365:9473], [366:7010], [367:5431],
[368:4620], [431:1A23], [620:C80D]. Answer the following
questions that examine the contents of PC, AR, AC, DR
and IR after the end of execution for the next instruction.
(.(Note: all numbers are in Hexadecimal
The content of IR after the end of execution
:for the next instruction is
4620 O
9473
5431
None of the choices
7010 O
Transcribed Image Text:Question Q: For a basic computer that is currently running in its timing TO of execution for an instruction that is located in memory location 366. The content of AC is (212) and the content of memory locations are as follow: [memory location: content]: [365:9473], [366:7010], [367:5431], [368:4620], [431:1A23], [620:C80D]. Answer the following questions that examine the contents of PC, AR, AC, DR and IR after the end of execution for the next instruction. (.(Note: all numbers are in Hexadecimal The content of IR after the end of execution :for the next instruction is 4620 O 9473 5431 None of the choices 7010 O
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