As shown in Fig. Q8, a uniform tensile stress creates a shear stress on crystal slip planes that lie at an angle 9 to the tensile axis. If the angle 0 is 45°, what is the shear stress on this plane caused by an applied tensile stress of 100 MPa? A. 70.7 MPa B. 50 MPa C. 0.019 MPa D. None of above Area A Area A cos e Tensile stress o F sin e F cos e 0 0 Fig. Q8 Force F F Shear stress T ✪

As shown in Fig. Q8, a uniform tensile stress creates a shear stress on crystal slip planes that lie at an angle 9 to the tensile axis. If the angle 0 is 45°, what is the shear stress on this plane caused by an applied tensile stress of 100 MPa? A. 70.7 MPa B. 50 MPa C. 0.019 MPa D. None of above Area A Area A cos e Tensile stress o F sin e F cos e 0 0 Fig. Q8 Force F F Shear stress T ✪

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

If we want to measure the stress of a flat non-uniform component, what should we pay attention to before the measurement?
A Single Crystal f coppor is or untad forr a temle test Suh that its Slip plane normal makes an angle o 65 with the tenale aocis thoree Possible slip dirators makes angle of G0; 48° and 28 with the sanme tensile axis whih thise three dirartions slip favoured and. the writuial rusolved shear s most 4 opper in I. 19MPA will an applaud stness 4.2 MPa wil yuld the Sample justify.
3. Two specimens with the same dimensions and made from two different materials, A and B, were subjected to tensile testing. The percentage reduction in the area of the specimen made of material 'A' was calculated 3 times that of the specimen made of material B. In this case, O A lthe ductility of material A and B is equal O Bthe material A is brittle and material B is ductile O Cthe material B is more ductile than material A O D nhe material A is more ductile than material B 1. 20 O Aramak için buraya yazıin
The diagram below shows a microscopic metal rod with a single crystal structure whose orientation is indicated by the inset. A force of F = 25.8 N is applied to the rod. The cross-sectional area is 1.9 mm². Calculate the shear stress along the close-packed direction. O a. 5.10 MPa O b. 6.10 MPa c. 4.66 MPa O d. 5.54 MPa Oe. 4.05 MPa
A 2.0-inch diameter 4140 steel bar is austenized and tempered in oil without Agitation, determine the resulting hardness at 0.6 inches below the surface, present all the Procedure to get to the answer
If the true stress is 74 MPa for the specimen described above elongated by 2.6 cm, what is the difference between nominal and true stress in MPa (absolute value)?
If a rod of single-crystal copper (FCC) is pulled in tension in the [210] direction (i.e. force direction) at a tensile stress of 50 MPa, slip will occur in the [0 1 1] direction on the (1 1 -1) plane. Use this information to answer the following questions. Which of the following is the critical resolved shear stress on the slip plane in the slip direction? Group of answer choices 24.49 MPa 34.65 MPa 12.25 MPa 102 MPa
Fill in the blanks: A tensile test is carried out to determine the strength constant C and strain-rate sensitivity exponent m for a certain metal at 1000°F. If temperature were decreased to 900°F, the strength constant C would . .and the strain- rate sensitivity exponent m would. . Select one: a. C would stay constant, m would Decrease b. Nothing would change c. C would Increase, m would Decrease d. C would Increase, m would stay constant e. C would Decrease, m would Increase
1. There are three slip systems on a FCC octahedral plane, i.e. one of the {111} planes. Assume a2 MPa tensile stress is applied along the [100] direction of a gold single crystal, whose criticalresolved shear stress is 0.91 MPa at room temperature. Demonstrate quantitatively thatmeasurable slip will not occur on any of the three slip systems containing the (111) plane as aresult of this applied tensile stress. (Hint: Schmid’s law) 2. Identify the Burgers vector (using vector notation) of a screw dislocation that can cross-slipbetween (111) and (111) planes of an FCC crystal (Hint: Use Weiss zone law). 3. Why are dislocations not considered thermodynamic equilibrium defects like vacancies?Explain by describing the relative interplay between entropy and enthalpy affecting the Gibbsfree energy of the dislocations-containing material system.
A steel pipe with an outside diameter of 115 mm and an inside diameter of 105 mm supports the loadings shown. Assume a = 510 mm, b = 230 mm, P = 20 kN, P, = 16 kN, and P; = 11 kN. (a) Determine the normal and shear stresses on the top surface of the pipe at point H. (b)Determine the principal stresses and maximum in-plane shear stress magnitude at point H and show the orientation of these stresses on an appropriate sketch. a P: P H K
Asiacell l. ZA0 @ 团 / photo_2021-02-18_13-04... 200 stress 150 (MPa) 100 50 0.1 0-2 0.3 strain From the tensile stress -strain behavior for the brass specimen ,cP the diameter is 12-8 mm Calculat e the follouding :- 1- The Yield stress , 2-Modulus of elasticity. - The Tensile strength .
Consider an iron single crystal with CCC crystal structure oriented in such a way that a tensile stress is applied to the along one direction [010]. a) Calculate the shear stress resolved along a plane (110) and a direction when a tensile stress of 52 MPa is applied. The normal to the slip plane forms 45° with traction direction. the direction of slip forms 55º with the traction direction. b) If the slip occurs in one plane (110) and in one direction and the critical resolved shear stress is 30 MPa, calculate the magnitude of tensile stress that must be applied to initiate the flow.