A Single Crystal f coppor is or untadforr a temletest Suh that its Slip plane normal makes anangle o 65 withthe tenale aocis thoreePossibleslip dirators makes angle of G0;48° and 28with the sanme tensile axiswhihthise threedirartionsslipfavoured and. the writuial rusolved shears most4 opper in I. 19MPAwillanapplaudstness4.2 MPa wil yuld theSample justify.

The slip will happen in the direction where the Schmid factor is highest. The three possible slip…

Answered: 6ingle Conystal t coppor is orented for…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q2 A tensile test specimen having a diameter of (10 mm) und a page length of (S0 mm) was tested to fracture The stieisitrain curve from the tensiotn test is shown in Figure (9) The lower plat is the expanded tegion OAT and associatod with the strain valuns tiven on the lower scale Determine, 480 Lpper veile AB 241 Loser scale + The ultimaie stress, be The propotional limit, 120 e The fracture strees 4 The modulus of elasticity, OAK 0.04 0.0s 0.00 0.12 0.16 1.20 0K2 DANN 0.006 0.008 0.010 e T'he offiet yield stuen at 0.2%, Strain tmm/um) G The asial force ucting on the specireni whert t i uxtended by Figuie (3) a sans
%V I. lu. N « duxvlsgprb 10-25 AM Thu 25 Feb Done Chapter 4 (3 of 19) 19 Eedetien 44 o ebe any an p eni th er +IL. The enber is sibjemd to a force ofFAN 2 45, deesiaa the man prndacd by Fabap polat A Reslving fore F into horiantal and vertical components, Rg a, and applying the principle of moments -.18 KN-m AN m iclockwise 3m bsin 45 kN (a) Thamer M. Korbasy ۳۷ مشارك آخر حمزه
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5KN 2 m A thin Cylinder has alength of thickness of 8 mm. Contain agas end of acylinder (deft) is fixied and tho right end o free- A rigid eglinder perpendiéulart ite longstudinal 2 m, internal diameter 60 cm, under af 5 MPa • apressure one 1 m is fixed to the free end f the axes (as shown infig of leugth arm A vertical load of 5KN is applied at the end of the rigid i Determine the maximun torsional stress i the wall the eglinder o termne the principal stresses in 3. Determine the max. strains (inchuding torsional strain) in the cylinder. arm the glindar 2.
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A laminae is considered a plate with only biaxial stresses in plane stress conditions. From Generalized Hooke’sLaw that you learnt in Strength of Materials, we know these equations to be true in such conditions. Or in other words, we know the Compliance matrix that represents the laminae. Find the Stiffness matrix of thesame laminae. Or in other words, prove that the equations below are true for the same laminae. The equationsbelow are what we discussed in Lecture. Assume the laminae has isotropic properties.

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