A tape weighting 2 lb (A=0.006 sq.in.); E=29,000,000 psi) has a length of 100.00 ft under a pull of 10 lb when supported for its full length. The tape is used to measure a line with the tape supported at its ends and in the center with a pull of 35 lb. if the value obtained is 2686.xx ft., what should the correct distance be? Know: W= 2 lb. L₁= 100.00 ft. P₁= 10 lb A=0.006 sq. in. total measured distance= 2686.xx ft. Find sage correction, pulling correction and true measured distance E=29,000,000 psi p= 35 lb

International Edition---engineering Mechanics: Statics, 4th Edition
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Author:Andrew Pytel And Jaan Kiusalaas
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Chapter1: Introduction To Statics
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Asssignmnet 1
A tape weighting 2 lb (A=0.006 sq.in.); E=29,000,000 psi) has a length of 100.00 ft under a pull of 10 lb when
supported for its full length. The tape is used to measure a line with the tape supported at its ends and in the
center with a pull of 35 lb. if the value obtained is 2686.xx ft., what should the correct distance be?
Know: W= 2 lb.
L,= 100.00 ft.
P₁= 10 lb
A= 0.006 sq. in.
total measured distance=2686.xx ft.
Find sage correction, pulling correction and true measured distance
E=29,000,000 psi
p= 35 lb
Transcribed Image Text:Asssignmnet 1 A tape weighting 2 lb (A=0.006 sq.in.); E=29,000,000 psi) has a length of 100.00 ft under a pull of 10 lb when supported for its full length. The tape is used to measure a line with the tape supported at its ends and in the center with a pull of 35 lb. if the value obtained is 2686.xx ft., what should the correct distance be? Know: W= 2 lb. L,= 100.00 ft. P₁= 10 lb A= 0.006 sq. in. total measured distance=2686.xx ft. Find sage correction, pulling correction and true measured distance E=29,000,000 psi p= 35 lb
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