Living by Chemistry
2nd Edition
ISBN: 9781464142314
Author: Angelica M. Stacy
Publisher: W. H. Freeman
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Chapter U6.123, Problem 8E
Interpretation Introduction
Interpretation: The equilibrium constant for the dissociation of methyl violet needs to be explained.
Concept Introduction: The color change for an indicator occurs when the H+ ion concentration is equal to K. This happens when the concentration of HIn molecules is equal to the concentration of the In− ions.
Expert Solution & Answer
Answer to Problem 8E
Equilibrium constant for the dissociation of methyl violet is 10−1 .
Explanation of Solution
Color changes for an indicator is occurs if H+ ion concentration is equal to constant K.
pH is the negative logarithm of H+ ion concentration. Given, pH is 1. Therefore,
pH=1−log[H+]=1[H+]=10−1
Since, [H+]=K
Therefore, K value is 10−1 .
Conclusion
Equilibrium constant for the dissociation of methyl violet is 10−1 .
Chapter U6 Solutions
Living by Chemistry
Ch. U6.117 - Prob. 1TAICh. U6.117 - Prob. 1ECh. U6.117 - Prob. 2ECh. U6.118 - Prob. 1TAICh. U6.118 - Prob. 1ECh. U6.118 - Prob. 2ECh. U6.118 - Prob. 3ECh. U6.118 - Prob. 4ECh. U6.118 - Prob. 5ECh. U6.118 - Prob. 6E
Ch. U6.118 - Prob. 7ECh. U6.119 - Prob. 1TAICh. U6.119 - Prob. 1ECh. U6.119 - Prob. 2ECh. U6.119 - Prob. 5ECh. U6.119 - Prob. 6ECh. U6.120 - Prob. 1TAICh. U6.120 - Prob. 1ECh. U6.120 - Prob. 2ECh. U6.120 - Prob. 3ECh. U6.120 - Prob. 4ECh. U6.120 - Prob. 5ECh. U6.121 - Prob. 1TAICh. U6.121 - Prob. 1ECh. U6.121 - Prob. 2ECh. U6.121 - Prob. 3ECh. U6.122 - Prob. 1TAICh. U6.122 - Prob. 1ECh. U6.122 - Prob. 3ECh. U6.122 - Prob. 4ECh. U6.122 - Prob. 5ECh. U6.122 - Prob. 6ECh. U6.122 - Prob. 7ECh. U6.123 - Prob. 1TAICh. U6.123 - Prob. 1ECh. U6.123 - Prob. 2ECh. U6.123 - Prob. 3ECh. U6.123 - Prob. 4ECh. U6.123 - Prob. 5ECh. U6.123 - Prob. 6ECh. U6.123 - Prob. 7ECh. U6.123 - Prob. 8ECh. U6 - Prob. C23.1RECh. U6 - Prob. C23.2RECh. U6 - Prob. C23.3RECh. U6 - Prob. C23.4RECh. U6 - Prob. C23.5RECh. U6 - Prob. C24.I2RECh. U6 - Prob. C24.I3RECh. U6 - Prob. C24.I4RECh. U6 - Prob. C24.I5RECh. U6 - Prob. 1RECh. U6 - Prob. 2RECh. U6 - Prob. 3RECh. U6 - Prob. 4RECh. U6 - Prob. 5RECh. U6 - Prob. 6RECh. U6 - Prob. 7RECh. U6 - Prob. 8RECh. U6 - Prob. 9RECh. U6 - Prob. 10RECh. U6 - Prob. 1STPCh. U6 - Prob. 2STPCh. U6 - Prob. 3STPCh. U6 - Prob. 4STPCh. U6 - Prob. 5STPCh. U6 - Prob. 6STPCh. U6 - Prob. 7STPCh. U6 - Prob. 8STPCh. U6 - Prob. 9STPCh. U6 - Prob. 10STPCh. U6 - Prob. 11STPCh. U6 - Prob. 12STPCh. U6 - Prob. 13STPCh. U6 - Prob. 14STPCh. U6 - Prob. 15STPCh. U6 - Prob. 16STPCh. U6 - Prob. 17STPCh. U6 - Prob. 18STPCh. U6 - Prob. 19STPCh. U6 - Prob. 20STP
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