Chapter SR31, Problem 7P

Solution

Find the mean, median, mode(s), and range of the data.

Mean $=\$9.2$

Median $=\$8.9$

Mode $=no\mathrm{mod}e$

Range $=\$5.85$

Given:

Hourly rate of pay: $\$8.80,\$6.50,\$10.85,\$7.90,\$9.50,\$9,\$8.70,\$12.35$

Concept used:

• Mean is the sum of the values divided by the number of values.
• Median is the middle value of your data set when in order from least to greatest.
• The mode is the number that occurred the most often.
• The range is the difference between the highest and lowest values

Calculation:

Hourly rate of pay: $\$8.80,\$6.50,\$10.85,\$7.90,\$9.50,\$9,\$8.70,\$12.35$

Mean $=\frac{sumofallvalues}{no.ofvalues}$

  $\begin{array}{l}=\frac{8.80+6.50+10.85+7.90+9.50+9+8.70+12.35}{8}\\ =\frac{73.6}{8}\\ =9.2\end{array}$

Mean $=\$9.2$

Median $=middlevalueofyourdatasetwheninorderfromleasttogreatest$

Least to greatest order = $\$6.50,\$7.90,\$8.70,\$8.80,\$9,\$9.50,\$10.85,\$12.35$

Median $=\frac{8.80+9}{2}=\frac{17.8}{2}=\$8.9$

Mode $=datathatoccursmost$

Mode $=no\mathrm{mod}e$

Range $=Highestvalue-LowestValue$

  $\begin{array}{l}=12.35-6.50\\ =5.85\end{array}$

Range $=\$5.85$