Chapter SH, Problem 7.6MPS

To determine

To calculate: The dimensions of the rectangular field.

Answer to Problem 7.6MPS

The required length and width are $7.28,10.28$ .

Explanation of Solution

Given information:

The area of the field, $A=75\text{sq}\text{. ft}$

The length of the field $L=x$ .

The width of the field $B=x+3$ .

Formula used:

The area of the field

  $A=LB$

Calculation:

Consider the given information:

The area of the field, $A=75\text{sq}\text{. ft}$

The length of the field $L=x$ .

The width of the field $B=x+3$ .

The area of the field

  $\begin{array}{c}75=x\left(x+3\right)\\ 75=x^2+3x\\ x^2+3x-75=0\end{array}$

Solve the above equation.

  $L=x=7.28$

Calculate the width of the field.

  $\begin{array}{c}B=7.28+3\\ =10.28\end{array}$

Hence, the length and width are $7.28,10.28$ .