Chapter R.1, Problem 9E

To determine

The correct way to write $\frac{16}{24}$ in lowest terms, from the choices below:

$\begin{array}{ccc}\hfill \text{A}\text{. }\frac{16}{24}& =& \frac{8+8}{8+16}=\frac{8}{16}=\frac{1}{2}\hfill \\ \hfill \text{B}\text{. }\frac{16}{24}& =& \frac{4\cdot 4}{4\cdot 6}=\frac{4}{6}\hfill \\ \hfill \text{C}\text{. }\frac{16}{24}& =& \frac{8\cdot 2}{8\cdot 3}=\frac{2}{3}\hfill \\ \hfill \text{D}\text{. }\frac{16}{24}& =& \frac{14+2}{21+3}=\frac{2}{3}\hfill \end{array}$