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(a)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater
(b)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has a higher priority. In the case of comparison between isotopes, the one having the greater atomic mass gets the higher priority. If the substituents are attached by the same atom, then the set of atoms one bond away from the point of attachment is compared. In each set, the highest priority atoms are compared. If the sets of atoms one bond away from the point of attachment are identical, then the sets of atoms one additional bond away from the point of attachment are compared. If the higher priority groups attached to the double bonded carbon atoms are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups attached to the double bonded carbon atoms are on the opposite side of the double bond, the alkene is assigned E configuration. When more than one double bond is present, each is assigned E or Z configuration, and the location of each double bond appears immediately before the E or Z designation.
(c)
Interpretation:
E or Z configuration is to be assigned to each double bond wherever appropriate in the given molecule.
Concept introduction:
When assigning priorities to substituents, the atom having the greater atomic number has a higher priority. In the case of comparison between isotopes, the one having the greater atomic mass gets the higher priority. If the substituents are attached by the same atom, then the set of atoms one bond away from the point of attachment is compared. In each set, the highest priority atoms are compared. If the sets of atoms one bond away from the point of attachment are identical, then the sets of atoms one additional bond away from the point of attachment are compared. If the higher priority groups attached to the double bonded carbon atoms are on the same side of the double bond, the alkene is assigned Z configuration. If the higher priority groups attached to the double bonded carbon atoms are on the opposite side of the double bond, the alkene is assigned E configuration. When more than one double bond is present, each is assigned E or Z configuration, and the location of each double bond appears immediately before the E or Z designation.
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Chapter C Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
- Draw an MO diagram for the following moleculearrow_forwardCyclopropane and cyclobutane have similar strain energy despite the fact that the C—C—C bond angles of cyclopropane are much smaller than those of cyclobutane. Suggest an explanation for this observation, considering all sources of strain discussed in Chapter 4.arrow_forwardQ1. Please answer the following questions with respect to this structure. но. a) What is the hybridization of all atoms in the molecule? b) There are two double bonds in the molecule. For each, indicate the correct stereochemistry, by circling E or Z.arrow_forward
- Both cis and trans isomers exist for this molecule. Which one is more stable?arrow_forwardDraw the skeletal (line-bond) structure of [CH₃CH₂CHC(O)CH₂CH₂CH₃]⁻. Include all lone pairs and charges as appropriate. What do the brackets and the - exponent mean for this formula?arrow_forwardExamine the sigma bonding in ethene. What types of orbitals does each C atom use when forming sigma bonds to the H atoms? s orbial p orbitals Ohybrid orbitals Submit What type of orbital does each C atom use to form a sigma bond to the other C atom? s orbial p orbitals hybrid orbitals O Submit Now examine the pi bonding in ethene. What types of orbitals on the C atoms are used to form the pi bond? Os orbital p orbitals hybrid orbitals Submitarrow_forward
- Using your model, construct an energy diagram to show the variation in the free energy of the molecule as the FRONT ATOM is rotated CLOCKWISE from 0º to 360º in 60º increments. In your energy diagram, you should clearly show the relative energies of each conformer.arrow_forwardSelect the correct molecular geometry and bond angles around the carbocation: |||||………. trigonal pyramidal, 120° tetrahedral, 109.5° O tetrahedral, 105° trigonal planar, 120° trigonal pyramidal, 109.5°arrow_forwarda) Draw all Newman projections of your molecule's conformations in which the CH3 group and the H of the CHY2 group are positioned 'ANTI' to each other. Be sure to put in the correct X and Y atoms, bonded to the correct C atoms, for your molecule. X = FY=I Conformations = 60 deg and - 180 deg 60 deg dihedral angle = - 179.987 deg 180 deg · - dihedral angle = 179.814 degarrow_forward
- Hey, I want a simple explanation about this topic (stability of cycloalkanes) and when is the dstribution of the atoms (axial and equatorial) and how can I determine the most stable shape of compounds. With give examples. Please don't answer me by handwriting.arrow_forwardDetermine the degrees of unsaturation given the molecular structurearrow_forwardName according IUPAC rule, the following molecule (with configurations if needed). You will give the name as the following, X for the positions and no space between characters : (XE,XR,XS)-X-methyl... Он NH, ОНarrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning