Chapter A.5, Problem 39AYU

To determine

To find: Simplify the given in factored form.

Answer to Problem 39AYU

$\frac{x\left(3x+2\right)}{{\left(3x+1\right)}^2}$

Explanation of Solution

Given:

$\frac{\left(3x+1\right).2x-x^2.3}{{\left(3x+1\right)}^2}$

Calculation:

$\frac{\left(3x+1\right).2x-x^2.3}{{\left(3x+1\right)}^2}=\frac{\left(6x^2+2x\right)-3x^2}{{\left(3x+1\right)}^2}=\frac{\left(3x^2+2x\right)}{{\left(3x+1\right)}^2}=\frac{x\left(3x+2\right)}{{\left(3x+1\right)}^2}$