Chapter A.10, Problem 113AYU

To determine

To find: Theperiod $T$ of the pendulum.

Answer to Problem 113AYU

The time period is $8.88\text{sec}$ .

Explanation of Solution

Given:

The length of the pendulum is $l=64\text{feet}$ .

Calculation:

Consider the expression for the Time period of the pendulum is,

  $T=2\pi \sqrt{\frac{l}{32}}$

Then,

  $\begin{array}{c}T=2\pi \sqrt{\frac{64}{32}}\\ =2\left(3.14\right)\sqrt{2}\\ =8.88\text{sec}\end{array}$