a. Explanation Given info: For a residential customer using the Two Period Plan of $4.10, the electricity charge during “on peak” hours in a month ( x 1 ) is $0.148 per kilowatt hour (kWh) and the electricity charge during “off peak” hours in a month ( x 2 ) is $0.046 per kilowatt hour (kWh). The electricity cost in a month is y . Calculation: For the customer, the fixed cost that has to be paid for using the Two Period Plan is $4.10. In addition to the fixed cost, the customer has to pay $0.148 for each kilowatt hour (kWh) of electricity they use during “on peak” hours, denoted by ( x 1 ) . Along with this, the customer must also pay $0 b. To determine Identify the y -intercept, b 0 and the partial slopes b 1 and b 2 of the linear equation in a . c. To determine Calculate the cost for a customer who uses 200kWh of electricity during “on peak” hours and 800kWh of electricity during “off peak” hours during a month.

10th Edition

ISBN: 9780321989178

Author: Neil A. Weiss

Publisher: PEARSON

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Chapter A, Problem 11RP

To determine

Find the equation that expresses y in terms of x1 and x2.

To determine

Identify the y-intercept, b0 and the partial slopes b1 and b2 of the linear equation in a.

To determine

Calculate the cost for a customer who uses 200kWh of electricity during “on peak” hours and 800kWh of electricity during “off peak” hours during a month.

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Find the equation that expresses y in terms of x 1 and x 2 .

Solution Summary: The author calculates the monthly cost of electricity, y, by considering the fixed cost, as well as the number of kilowatt hours used during "on peak" hours.

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Find the equation that expresses y in terms of x1 and x2.

Identify the y-intercept, b0 and the partial slopes b1 and b2 of the linear equation in a.

Calculate the cost for a customer who uses 200kWh of electricity during “on peak” hours and 800kWh of electricity during “off peak” hours during a month.

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